Answer:
<span>5010J</span>
Explanation:
Work is force times distance, or
<span>W=F⋅d</span>.
Substitute in values from the question to get
<span>W=8.35⋅<span>102</span>N⋅6m=50.1⋅<span>102</span>Nm=5010<span>J</span></span>
I believe it's magnetic stripping. I hope that helps
a) 120 s
b) v = 0.052R [m/s]
Explanation:
a)
The period of a revolution in a simple harmonic motion is the time taken for the object in motion to complete one cycle (in this case, the time taken to complete one revolution).
The graph of the problem is missing, find it in attachment.
To find the period of revolution of the book, we have to find the time between two consecutive points of the graph that have exactly the same shape, which correspond to two points in which the book is located at the same position.
The first point we take is t = 0, when the position of the book is x = 0.
Then, the next point with same shape is at t = 120 s, where the book returns at x = 0 m.
Therefore, the period is
T = 120 s - 0 s = 120 s
b)
The tangential speed of the book is given by the ratio between the distance covered during one revolution, which is the perimeter of the wheel, and the time taken, which is the period.
The perimeter of the wheel is:
where R is the radius of the wheel.
The period of revolution is:
Therefore, the tangential speed of the book is:
What does this mean? What do you need help with?
As we know that in transformers we have
here we know that
now from above equation we will have
now we have to reduce this voltage to final voltage of V = 4 V
so again we will have
so we need to take such a winding whose ratio is 1:5
So it is satisfied in X
so answer will be
<u>B)- X</u>