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3 years ago

Which best describes the speed of the ball as it is thrown straight up into the air and comes back down

1 answer:

4 0

Assuming that up is the positive direction, the velocity of the ball goes from it's initial and approaches zero, which it reaches at the apex of it's height. After peaking, the velocity is now reaching the same numbers it had on the way up, only with a negative value this time. If it had a velocity of 5m/s upon leaving the hand, it will have a velocity of -5m/s when it came back to the hand.

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The barrel of a rifle has a length of 0.855 m. A bullet leaves the muzzle of a rifle with a speed of 553 m/s. What is the accele

Novay_Z [31]

Answer:

Acceleration of the bullet will be 1778835.6 $m/sec^2$

Explanation:

We have given length of the barrel refile s= 0.855 m

When the bullet leaves the muzzle its velocity is 553 m/sec

So final velocity v = 553 m/sec

Initial velocity will be 0 that is u = 0 m/sec

According to third equation of motion $v^2=u^2+2as$

$553^2=0^2+2\times a\times 0.855$

$a=178835.6m/sec^2$

5 0

3 years ago

Identify the following joint

MissTica

This is a ball and socket joint.

7 0

3 years ago

A long-distance swimmer is able to swim through still water at 4.0 km/h. She wishes to try to swim from Port Angeles, Washington

Roman55 [17]

Let $\theta$ be the direction the swimmer must swim relative to east. Then her velocity relative to the water is

$\vec v_{S/W}=\left(4.0\dfrac{\rm km}{\rm h}\right)(\cos\theta\,\vec\imath+\sin\theta\,\vec\jmath)$

The current has velocity vector (relative to the Earth)

$\vec v_{W/E}=\left(3.0\dfrac{\rm km}{\rm h}\right)\,\vec\imath$

The swimmer's resultant velocity (her velocity relative to the Earth) is then

$\vec v_{S/E}=\vec v_{S/W}+\vec v_{W/E}$

$\vec v_{S/E}=\left(\left(4.0\dfrac{\rm km}{\rm h}\right)\cos\theta+3.0\dfrac{\rm km}{\rm h}\right)\,\vec\imath+\left(4.0\dfrac{\rm km}{\rm h}\right)\sin\theta\,\vec\jmath$

We want the resultant vector to be pointing straight north, which means its horizontal component must be 0:

$\left(4.0\dfrac{\rm km}{\rm h}\right)\cos\theta+3.0\dfrac{\rm km}{\rm h}=0\implies\cos\theta=-\dfrac{3.0}{4.0}\implies\theta\approx138.59^\circ$

which is approximately 41º west of north.

6 0

3 years ago

The electromagnetic wave shown above is made of vibrating

Natasha2012 [34]

B. electric and magnetic fields.

Explanation:

This is a wave diagram of an electromagnetic wave showing vibration of both electric and magnetic fields.

An electromagnetic wave is made up of electric and magnetic fields vibrating.

These waves are deflected neither by electric fields nor magnetic fields.
The electromagnetic field is made up of a broad range of radiations.
Visible light is an electromagnetic radiation.
The magnetic and electric fields are oriented perpendicularly and they are transverse waves.

Learn more:

Electromagnetic waves brainly.com/question/12450147

#learnwithBrainly

3 0

3 years ago

[WASSCE June 2008 Qu 11]

NISA [10]

α=30°

F=20 N

Fh=F*cos(α)

Fv=F*cos(90-α)=F*sin(α) (vertical component of the force F)

Fv=20*0,5=10.00 N

Answer (C)

4 0

3 years ago