A fish of 108 N is attached to the end of a dangling spring, stretching the spring by 14.0 cm. What is the mass of a fish that w
1 answer:
Answer:
The mass of the fish is 18.1 kg.
Explanation:
Given;
weight of the fish, F = 108 N
extension of the spring by the given weight, x = 14 cm = 0.14 m
First, determine the elastic constant of the spring by applying Hook's law;
F = kx
where;
k is the spring constant
k = F/x
k = 108 / 0.14
k = 771.43 N/m
When the spring is stretched to 23cm, the mass of the fish is calculated as follows;
Therefore, the mass of the fish is 18.1 kg.
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Answer:
2.83
Explanation:
Kepler's discovered that the square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit, that is called Kepler's third law of planet motion and can be expressed as:
(1)
with T the orbital period, M the mass of the sun, G the Cavendish constant and a the semi major axis of the elliptical orbit of the planet. By (1) we can see that orbital period is independent of the mass of the planet and depends of the semi major axis, rearranging (1):
(2)
Because in the right side of the equation (2) we have only constant quantities, that implies the ratio is constant for all the planets orbiting the same sun, so we can said that: