A fish of 108 N is attached to the end of a dangling spring, stretching the spring by 14.0 cm. What is the mass of a fish that w
1 answer:
Answer:
The mass of the fish is 18.1 kg.
Explanation:
Given;
weight of the fish, F = 108 N
extension of the spring by the given weight, x = 14 cm = 0.14 m
First, determine the elastic constant of the spring by applying Hook's law;
F = kx
where;
k is the spring constant
k = F/x
k = 108 / 0.14
k = 771.43 N/m
When the spring is stretched to 23cm, the mass of the fish is calculated as follows;
Therefore, the mass of the fish is 18.1 kg.
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electrons
Explanation:
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k is the Coulomb's constant
Q is the charge stored on the sphere
r is the distance (from the centre of the sphere) at which the field is calculated
In this problem, the cloud is assumed to be a charged sphere, so we have:
is the maximum electric field strength tolerated by the air before breakdown occurs
is the radius of the sphere
Re-arranging the equation for Q, we find the maximum charge that can be stored on the cloud:
Assuming that the cloud is negatively charged, then
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The number of excess electrons on the cloud is