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EastWind [94]
3 years ago
15

Jim thinks that he can throw a baseball six meters per second. What does the six meters refer to?

Physics
2 answers:
Mnenie [13.5K]3 years ago
6 0

Answer:

The distance the baseball travels in one second.

Explanation:

SVETLANKA909090 [29]3 years ago
3 0

Answer:

Six meters refers to the distance the baseball travels in one second.

Explanation:

6 m/s means that every second, the baseball travels 6m. So, 6 meters is the distance traveled in one second.

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Solve for M₂
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Explanation:

M₂ = Fr²/GM₁

M₂ = [(132N)(.243m)²]/[(6.67*10^-11N*m²/kg)(1.175*10^4kg)]

M₂ = (7.79N*m²)/(7.84*10^-7N*m²)

M₂ = 9.94*10^6 kg

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3 years ago
Which two particles are found in the center of an atom
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the two particles that are found in the center of an atom are protrons and neutrons.

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In a standing wave, areas of destructive are the?
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antinodes

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3 years ago
A 2.8-carat diamond is grown under a high pressure of 58 × 10 9 N / m 2 .
Rzqust [24]

Answer:

a)  ΔV = 2,118 10⁻⁸ m³   b)  ΔR= 0.0143 cm

Explanation:

a) For this part we use the concept of density

    ρ = m / V

As we are told that 1 carat is 0.2g we can make a rule of proportions (three) to find the weight of 2.8 carats

    m = 2.8 Qt (0.2 g / 1 Qt) = 0.56 g = 0.56 10-3 kg

   

    V = m / ρ

    V = 0.56 / 3.52

    V = 0.159 cm3

We use the relation of the bulk module

    B = P / (Δv/V)

    ΔV = V P / B

    ΔV = 0.159 10⁻⁶ 58 10⁹ /4.43 10¹¹

    ΔV = 2,118 10⁻⁸ m³

b) indicates that we approximate the diamond to a sphere

    V = 4/3 π R³

For this part let's look for the initial radius

    R₀ = ∛ ¾ V /π

    R₀ = ∛ (¾ 0.159 /π)

    R₀ = 0.3361 cm

Now we look for the final volume and with this the final radius

    V_{f} = V + ΔV

    V_{f} = 0.159 + 2.118 10⁻²

    V_{f} = 0.18018 cm3

    R_{f} = ∛ (¾ 0.18018 /π)

    R_{f} = 0.3504 cm

The radius increment is

    ΔR = R_{f} - R₀

    ΔR = 0.3504 - 0.3361

    ΔR= 0.0143 cm

4 0
3 years ago
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