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2 years ago

15

Jim thinks that he can throw a baseball six meters per second. What does the six meters refer to?

2 answers:

Mnenie [13.5K]2 years ago

6 0

Answer:

The distance the baseball travels in one second.

Explanation:

SVETLANKA909090 [29]2 years ago

3 0

Answer:

Six meters refers to the distance the baseball travels in one second.

Explanation:

6 m/s means that every second, the baseball travels 6m. So, 6 meters is the distance traveled in one second.

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An Olympic swimmer swims 50.0 meters in 23.1 seconds . What is his average speed

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If you take 50 meters and divide by 23.1 seconds, you will get 2.16 meters per second.

So his average speed is 2.16 m/s.

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3 years ago

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dexar [7]

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PLEASE HELP ASAP!!

Phantasy [73]

According to the information in the fragment, it can be inferred that it is an example of how scientific development has consequences on pre-established theories and new areas are created in science (option C)

<h3>What is a scientific theory?</h3>

A scientific theory is a term to refer to a set of concepts and observations that are proposed as principles to explain a class of phenomena.

According to the above, the discovery of germs and their relationship with human diseases was an event that changed scientific theories about human diseases because it demonstrated a different explanation than what was believed up to that time.

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Learn more about sciences in: brainly.com/question/12265124

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4 0

2 years ago

Four point charges are placed at the corners of a square. Each charge has the identical value +Q. The length of the diagonal of

kvv77 [185]

Answer: $V_{net}=4\frac{kQ}{a}$

Explanation:

Given

charge on each Particle is Q

Length of diagonal of the square is 2a

therefore distance between center and each charge is $\frac{2a}{2}=a$

Electric Potential of charged Particle is given by

For First Charge

$V_1=\frac{kQ}{a}$

$V_2=\frac{kQ}{a}$

$V_3=\frac{kQ}{a}$

$V_4=\frac{kQ}{a}$

total Electric Potential At center is given by

$V_{net}=V_1+V_2+V_3+V_4$

$V_{net}=4\times \frac{kQ}{a}$

$V_{net}=4\frac{kQ}{a}$

7 0

3 years ago