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nexus9112 [7]
3 years ago
7

Determine the force of gravitational attraction between the Earth and the moon. Their masses are 5.98 x 1024 kg and 7.26 x 1022

kg, respectively
Physics
1 answer:
monitta3 years ago
4 0

Answer:

F=1.95\times 10^{20}\ N

Explanation:

Mass of Earth, m_e=5.98 \times 10^{24}\ kg

Mass of Moon, m_m=7.26\times 10^{22}\ kg

The distance between Earth and the Moon is, d=384,400\ km

We need to find the force of gravitational attraction between the Earth and the moon. The force of gravity is given by :

F=G\dfrac{m_em_m}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{5.98 \times 10^{24}\times 7.26\times 10^{22}}{(384400 \times 10^3)^2}\\\\F=1.95\times 10^{20}\ N

So, the required force is 1.95\times 10^{20}\ N.

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The resolution of a telescope is ultimately limited by the diameter of its objective lens or mirror. A typical amateur astronome
slava [35]

Answer:

 θ =  3.19  arc second

Explanation:

The resolution of a telescope is given by the rayleigh criterion, which establishes that two objects are separated if the principal maximum of diffraction of one of them coincides with the first minimum of diffraction of the second object, based on this the solution is given by the first diffraction minimum, the a slit is

        a sin θ = m λ

with m = 1

in the case of circular apertures the equation must be found in polar coordinates, therefore a numerical constant is introduced

        a sin θ = 1.22 λ

Angles are measured in radians and in these experiments they are small

        sin θ = θ

       θ= 1.22  λ  / a

in this case a = 6.09 in, the wavelength is wrong = 550 10⁻⁹ m which is the maximum resolution of the human eye

l

et's reduce the magnitudes to the SI system

        d = 6.09‘  2.54 10⁻-2 m / 1 inch = 15.4686 10-2 m

let's calculate

       θ = 1.22 550 10-9 / 15.468 10-2

       θ = 15.5 10⁻⁶ rad

       rad = 2.06 105 s

       θ = 15.5 10⁻⁶ rad  2.06 105s/ 1 rad

       θ =  3.19   s

     

3 0
2 years ago
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andreyandreev [35.5K]

Answer:

b

Explanation:

8 0
2 years ago
Two parallel wires are separated by 6.10 cm, each carrying 2.85 A of current in the same direction. (a) What is the magnitude of
Westkost [7]

Answer:

The force per unit length is 2.66 \times 10^{-5} \ N/m

Explanation:

The current carrying by each wires = 2.85 A

The current in both wires flows in same direction.

The gap between the wires = 6.10 cm

Now we will use the below expression for the force per unit length. Moreover, before using the below formula we have to change the unit centimetre into meter. So, we just divide the centimetre with 100.

F/l = \frac{\mu _0i_1 i_2}{2\pi d} \\i_1 = 2.85 \\i_ 2 = 2.85  \\\mu _0 = 4\pi \times 10^{-7} \\d = 0.061 \\F/l = \frac{4\pi \times 10^{-7} \times 2.85 \times 2.85}{2 \pi \times 0.061} \\= 2.66 \times 10^{-5} \ N/m

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3 years ago
4. What does doubling the voltage do to the strength of the electromagnet?​
Naya [18.7K]

Answer:

it can make it stronger!

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