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nexus9112 [7]
3 years ago
7

Determine the force of gravitational attraction between the Earth and the moon. Their masses are 5.98 x 1024 kg and 7.26 x 1022

kg, respectively
Physics
1 answer:
monitta3 years ago
4 0

Answer:

F=1.95\times 10^{20}\ N

Explanation:

Mass of Earth, m_e=5.98 \times 10^{24}\ kg

Mass of Moon, m_m=7.26\times 10^{22}\ kg

The distance between Earth and the Moon is, d=384,400\ km

We need to find the force of gravitational attraction between the Earth and the moon. The force of gravity is given by :

F=G\dfrac{m_em_m}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{5.98 \times 10^{24}\times 7.26\times 10^{22}}{(384400 \times 10^3)^2}\\\\F=1.95\times 10^{20}\ N

So, the required force is 1.95\times 10^{20}\ N.

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Based on the simple blackbody radiation model described in class, answer the following question. The planets Mars and Venus have
Lera25 [3.4K]

Answer:

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Explanation:

From the question we are told that

     The albedo value of Mars is  A_1  = 0.15

      The albedo value of Mars is  A_2  = 0.15

       The surface temperature of Mars is  T_1 = 220 K

        The surface temperature of Venus is  T_2 = 700 K

          The distance of Mars from the sun is d_m = 2.28*10^8 \ km = 2.28*10^8* 1000 = 2.28*10^{11} \  m

          The distance of Venus from sun is  d_v = 1.08 *10^{8} \ km = 1.08 *10^{8} * 1000 =  1.08 *10^{11} \ m

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          T = [\frac{E R^2 (1- A_1)}{\sigma d_m} ]

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         T = \frac{6.28 *10^{7} * (7*10^8)^2 * (1-0.15)}{(5.67 *10^{-8}) * (2.28 *10^{11})^2)}

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           G_m =  T -  T_1

           G_m =  307 - 220

          G_m =  87 K

   

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