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3 years ago

A monatomic gas is measured to have an average speed of 1477 m/s. If the

Physics

1 answer:

lana [24]3 years ago

3 0

Answer:

The temperature of the gas is 350.02 K.

Explanation:

The average speed is related to the temperature as follows:

$\bar v = \sqrt{\frac{3RT}{M}}$ (1)

Where:

$\bar v$ : is the average speed = 1477 m/s

R: is the gas constant = 8.31 J/(K*mol)

T. is the temperature =?

M: is the molar mass

First, let's find the molar mass:

$M = \frac{m}{n}$

Where:

m: is the mass of the gas = 0.008 kg

n: is the number of moles = 2 mol

$M = \frac{m}{n} = \frac{0.008 kg}{2 mol} = 0.004 kg/mol$

Hence, by solving equation (1) fot T we have:

$T = \frac{\bar v^{2}*M}{3R} = \frac{(1477 m/s)^{2}*0.004 kg/mol}{3*8.31 J/(K*mol)} = 350.02 K$

Therefore, the temperature of the gas is 350.02 K.

I hope it helps you!

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lesya [120]

Answer:

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3 years ago

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A bicycle is traveling north at 5.0 m/s. The mass of the wheel, 2.0 kg, is uniformly distributed along the rim, which has a radi

andreev551 [17]

Answer:2

Explanation:

Given

Velocity of bicycle is 5 m/s towards north

radius of rim $r=20 cm$

mass of rim $m=2 kg$

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$I=mr^2=2\times 0.2^2=0.08 kg-m^2$

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3 years ago

Polonium, the Period 6 member of Group 6A(16), is a rare radioactive metal that is the only element with a crystal structure bas

Burka [1]

Answer:

Approximate atomic radius for polonium-209 is 167.5 pm .

Explanation:

Number of atom in simple cubic unit cell = Z = 1

Density of platinum = $9.232 g/cm^3$

Edge length of cubic unit cell= a = ?

Atomic mass of Po (M) = 209 g/mol

Formula used :

$\rho=\frac{Z\times M}{N_{A}\times a^{3}}$

where,

ρ = density

Z = number of atom in unit cell

M = atomic mass

$(N_{A})$ = Avogadro's number

a = edge length of unit cell

On substituting all the given values , we will get the value of 'a'.

$9.232 g/cm3=\frac{1 \times 209 g/mol}{6.022\times 10^{23} mol^{-1}\times (a)^{3}}$

$a = 3.35\times 10^{-8} cm$

Atomic radius of the polonium in unit cell = r

r = 0.5a

$r=0.5\times 3.35\times 10^{-8} cm=1.675\times 10^{-8} cm$

$1 cm = 10^{10} pm$

$1.675\times 10^{-8} cm=1.675\times 10^{-8}\times 10^{10}=167.5 pm$

Approximate atomic radius for polonium-209 is 167.5 pm.

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3 years ago

Please help thank you

Margarita [4]

Answer:

$\theta \approx 59.036^{\circ}$ , $T_{2} \approx 23.324\,N$

Explanation:

First we build the Free Body Diagram (please see first image for further details) associated with the mass, we notice that system consist of a three forces that form a right triangle (please see second image for further details): (i) The weight of the mass, (ii) two tensions.

The requested tension and angle can be found by the following trigonometrical and geometrical expressions:

$\theta = \tan^{-1} \frac{W}{T_{2}}$ (1)