Answer:
Mass = 176 g
Explanation:
Given data:
Volume of CH₄ = 89.6 L
Mass of CO₂ formed = ?
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O
one mole of any gas at STP occupy 22.4 L volume.
number of moles of CH₄ that occupy 89.6 L = 89.6/22.4 = 4 mol
Now we will compare the moles of CH₄ and CO₂:
CH₄ : CO₂
1 : 1
4 : 4
Mass of CO₂:
Mass = number of moles × molar mass
Mass = 4 mol × 44 g/mol
Mass = 176 g
Answer:
Mass = 234 g
Explanation:
Given data:
Mass of NaCl produced = ?
Moles of chlorine = 2.0 mol
Solution:
Chemical equation:
2Na + Cl₂ → 2NaCl
now we will compare the moles of NaCl with chlorine gas.
Cl₂ : NaCl
1 : 2
2.0 : 2/1×2.0 = 4.0 mol
Mass of NaCl;
Mass = number of moles × molar mass
Mass = 4.0 mol × 58.5 g/mol
Mass = 234 g
Answer:
the material will be water and oxygen
Covalent bonds but not ionic