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kramer
2 years ago
15

How many moles of chloride ions are there in 2.5 L of 5 M magnesium chloride?

Chemistry
1 answer:
castortr0y [4]2 years ago
4 0

Answer:

n_{Cl^-}=25molCl^-

Explanation:

Hello,

In this case, since the given 5-M concentration of magnesium chloride is expressed as:

5\frac{molMgCl_2}{L}

We can notice that one mole of salt contains two moles of chloride ions as the subscript of chlorine is two, in such a way, with the volume of solution we obtain the moles of chloride ions as shown below:

n_{Cl^-}=5\frac{molMgCl_2}{L}*\frac{2molCl^-}{1molMgCl_2} *2.5L\\\\n_{Cl^-}=25molCl^-

Best regards.

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The mass of dissolved sodium carbonate is 109 g of Na₂CO₃.

<h3>What is a solution ?</h3>

A solution consists of two elements , a solute and a solvent .

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The concentration of a solution is measure by Molarity , Molality , mass% etc.

It is given in the question that

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