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3 years ago

How many moles of chloride ions are there in 2.5 L of 5 M magnesium chloride?

Chemistry

1 answer:

castortr0y [4]3 years ago

4 0

Answer:

$n_{Cl^-}=25molCl^-$

Explanation:

Hello,

In this case, since the given 5-M concentration of magnesium chloride is expressed as:

$5\frac{molMgCl_2}{L}$

We can notice that one mole of salt contains two moles of chloride ions as the subscript of chlorine is two, in such a way, with the volume of solution we obtain the moles of chloride ions as shown below:

$n_{Cl^-}=5\frac{molMgCl_2}{L}*\frac{2molCl^-}{1molMgCl_2} *2.5L\\\\n_{Cl^-}=25molCl^-$

Best regards.

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What volume (mL) of the partially neutralized stomach acid having concentration 2 M was neutralized by 0.1 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)

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$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

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