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3 years ago

How many moles of chloride ions are there in 2.5 L of 5 M magnesium chloride?

Chemistry

1 answer:

castortr0y [4]3 years ago

4 0

Answer:

$n_{Cl^-}=25molCl^-$

Explanation:

Hello,

In this case, since the given 5-M concentration of magnesium chloride is expressed as:

$5\frac{molMgCl_2}{L}$

We can notice that one mole of salt contains two moles of chloride ions as the subscript of chlorine is two, in such a way, with the volume of solution we obtain the moles of chloride ions as shown below:

$n_{Cl^-}=5\frac{molMgCl_2}{L}*\frac{2molCl^-}{1molMgCl_2} *2.5L\\\\n_{Cl^-}=25molCl^-$

Best regards.

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3 years ago

a sample of unknown material weighs 500 n in air and 200 n when immesersed in alcholol with a specfic gravity of 0.7 what is the

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Formula used to calculate Buoyant force is as follows.

$F_{B} = F_{air} - F_{alc}\\= 500 - 200 \\= 300 N$

Hence, volume of the material is calculated as follows.

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$\rho$ = specific gravity

g = acceleration due to gravity = 9.81

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2 years ago

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2 years ago

The density of a metal is 11.4 g/cm3. How much volume (in cm3) would a sample of 30.5 g have?

julia-pushkina [17]

<u>The Concept:</u>

We are given the density of a sample of the metal = 11.4 grams / cm³

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2 years ago