3 years ago

Help me pretty pls :)

1 answer:

8 0

APC your welcome mark me brainliest please

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dsp73

We have:

$cot(-x)cos(-x)+sin(-x)=-\frac{1}{f(x)}$

Then we use trigonometric identities to change the negative sign of the trigonometric functions, so:

$-sin(x)-cot(x)cos(x)=-\frac{1}{f(x)}$

We clear f(x):

$f(x)=\frac{1}{sin(x)+cot(x)cos(x)}=\frac{1}{sin(x)+\frac{cos(x)}{sin(x)}cos(x)}=\frac{1}{sin(x)+\frac{cos^2(x)}{sin(x)}}$

we simply what we can:

$f(x)=\frac{1}{\frac{sin^2(x)+cos^2(x)}{sin(x)}}=sin(x)$

Thus, the correct answer is;

$f(x)=sin(x)$

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1 year ago