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dedylja [7]
3 years ago
14

Help me pretty pls :)

Mathematics
1 answer:
Zarrin [17]3 years ago
8 0
APC your welcome mark me brainliest please
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Hanukkah is an eight day Jewish cele bration which is observed in November or December, as determined by the Hebrew calendar. On
tatiyna

Answer:

30 feet

Step-by-step explanation:

Interesting question.

  • 1 cubit = 18 inches
  • 20 cubits = x
  • 1/20 = 18/x       Cross multiply
  • x = 20 * 18
  • x = 360 inches.

The maximum height is 360 inches.

  • 1 foot = 12 inches
  • x feet = 360 inches   Cross multiply
  • 12x = 360 * 1
  • 12x/12 = 360/12
  • x = 30

The maximum height reached was 30 feet.


6 0
3 years ago
Read 2 more answers
Which relationship has a domain of real numbers?
babunello [35]

Answer:Domain: all x-values that are to be used (independent values).

Step-by-step explanation:The domain is the set of all first elements of ordered pairs (x-coordinates). The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range. Domain: all x-values that are to be used (independent values).

7 0
3 years ago
What is the y-intercept of the line represented by the equation?<br><br><br><br> y = –6x – 1
ValentinkaMS [17]
If the equation of a line is written in the y=mx+b form, b is the y-intercept.

y=-6x-1 \\&#10;b=-1

The y-intercept is -1. The line crosses the y-axis at the point (0,-1).
8 0
3 years ago
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A bakery bakes 728 trays of cookies in a day. How many trays of cookies can the bakery make in 43 days?
musickatia [10]

Answer:

There will be 31,304 trays of cookies in 43 days.

Step-by-step explanation:

728 = 1 day

728 x 43 = 31,304

5 0
3 years ago
Find all points on the portion of the plane x+y+z=5 in the first octant at which f(x, y, z) = xy2z2 has a maximum value.
irina1246 [14]
Lagrange multipliers:

L(x,y,z,\lambda)=xy^2z^2+\lambda(x+y+z-5)

L_x=y^2z^2+\lambda=0
L_y=2xyz^2+\lambda=0
L_z=2xy^2z+\lambda=0
L_\lambda=x+y+z-5=0

\lambda=-y^2z^2=-2xyz^2=-2xy^2z

-y^2z^2=-2xyz^2\implies y=2x (if y,z\neq0)

-y^2z^2=-2xy^2z\implies z=2x (if y,z\neq0)

-2xyz^2=-2xy^2z\implies z=y (if x,y,z\neq0)

In the first octant, we assume x,y,z>0, so we can ignore the caveats above. Now,

x+y+z=5\iff x+2x+2x=5x=5\implies x=1\implies y=z=2

so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of f(1,2,2)=16.

We also need to check the boundary of the region, i.e. the intersection of x+y+z=5 with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force f(x,y,z)=0, so the point we found is the only extremum.
4 0
3 years ago
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