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Allisa [31]
2 years ago
7

What is the energy equivalent of 5.0kg of mass?

Physics
2 answers:
DiKsa [7]2 years ago
7 0

Answer : The energy equivalent if 5 kg of mass is 4.5\times 10^{17}\ J

Explanation :

Given that,

Mass, m = 5 kg

From Einstein's mass - energy equivalence relation :

E=mc^2

E is energy

m is the mass of the object

c is the speed of light

E=5\ kg\times (3\times 10^8\ m/s)^2

E=4.5\times 10^{17}\ J

Hence, this is the required solution.

Ira Lisetskai [31]2 years ago
3 0
Ah hah !  Sounds to me like an  " E = m c² "  question.

c = 3 x 10⁶  m/s

c² = 9 x 10¹² m²/s²

                       E  =  (5 kg)  x  (9 x 10¹² m²/s²)

                           =       45 x 10¹²  kg-m²/s²

                           =       4.5 x 10¹³  newton-m

                           =        4.5 x 10¹³ Joules  . 

That's the energy needed to

-- run a 1000-watt blow-dryer for roughly  1,427 years .
or
-- run a 400-horsepower truck, wide open, pedal to the metal,
   for   4.78 years . 
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A weightlifter lifts a 1250-N barbell 2 m in 3 s.How much power was used to lift the barbell?
Vlad [161]

The power is 833.3 W

Explanation:

First of all, we need to calculate the work done in lifting the barbell, which is equal to the change in gravitational potential energy of the barbell:

W=(mg)h

where

mg = 1250 N is the weight of the barbell

h = 2 m is the change in height

Substituting,

W=(1250)(2)=2500 J

Now we can calculate the power, which is equal to the work done per unit time:

P=\frac{W}{t}

where

W = 2500 J is the work done

t = 3 s is the time taken

Substituting,

P=\frac{2500}{3}=833.3 W

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

5 0
2 years ago
A 2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 V. What are (a) the total energy stored i
Debora [2.8K]

Answer:

(A) Total energy will be equal to 0.044\times 10^{-5}J

(b) Energy density will be equal to 0.0175J/m^3

Explanation:

We have given diameter of the plate d = 2 cm = 0.02 m

So area of the plate A=\pi r^2=3.14\times 0.02^2=0.001256m^2

Distance between the plates d = 0.50 mm = 0.50\times 10^{-3}m

Permitivity of free space \epsilon _0=8.85\times 10^{-12}F/m

Potential difference V =200 volt

Capacitance between the plate is equal to C=\frac{\epsilon _0A}{d}=\frac{8.85\times 10^{-12}\times 0.001256}{0.50\times 10^{-3}}=0.022\times 10^{-9}F

(a) Total energy stored in the capacitor is equal to

E=\frac{1}{2}CV^2

E=\frac{1}{2}\times 0.022\times 10^{-9}\times 200^2=0.044\times 10^{-5}J

(b) Volume will be equal to V=Ad, here A is area and d is distance between plates

V=0.001256\times 0.02=2.512\times 10^{-5}m^3

So energy density =\frac{Energy}{volume}=\frac{0.044\times 10^{-5}}{2.512\times 10^{-5}}=0.0175J/m^3

7 0
3 years ago
Why is a minimum of three seismic stations needed to find the epicenter of an earthquake?
vazorg [7]

Each station can detect how far away the epicenter was. So each station basically has a circle made of possible epicenters. When you have three, you narrow it down to one, final point.

5 0
3 years ago
A rescue airplane is diving at an angle of 37º below the horizontal with a speed of 250 m/s. It releases a survival package when
alisha [4.7K]

Answer:

<em>The correct option is 1.  720 m</em>

Explanation:

<u>Projectile Motion</u>

When an object is launched in free air (no friction) with an initial speed vo at an angle \theta, it describes a curve which has two components: one in the horizontal direction and the other in the vertical direction. The data provided gives us the initial conditions of the survival package's launch.

\displaystyle V_o=250\ m/s

\displaystyle \theta =-37^o

The initial velocity has these components in the x and y coordinates respectively:

\displaystyle V_{ox}=250\ cos(-37^o)=199.7\ m/s

\displaystyle V_{oy}=250\ sin(-37^o)=-150.5\ m/s

And we know the plane has an altitude of 600 m, so the package will reach ground level when:

\displaystyle y=-600\ m

The vertical distance traveled is given by:

\displaystyle y=V_{oy}\ t-\frac{g\ t^2}{2}=-600

We'll set up an equation to find the time when the package lands

\displaystyle -150.5t-4.9\ t^2=-600

\displaystyle -4.9\ t^2-150.5\ t+600=0

Solving for t, we find only one positive solution:

\displaystyle t=3.6\ sec

The horizontal distance is:

\displaystyle x=V_{ox}.t=199.7\times3.6=720\ m

The correct option is 1.  720 m

6 0
3 years ago
35 POINTS!!!!!!! WILL MARK BRAINLIEST!!!!! PLZ HURRY, TIMED!!!!!!!!!!!!!!! thanks
Sidana [21]

Answer:

<em>Well, Your best answer will be is Column 1 should be titled “Time,” and Column 2 should be titled  "Velocity". </em><em>So, The best answer is </em><u><em>Choice 1.</em></u>

<em> </em>

<em />

7 0
3 years ago
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