Which of these results from cell division?

Question 26 Suppose a flask is filled with of and of . The following reaction becomes possible: The equilibrium constant for thi

Blizzard [7]

Answer:

0.36 M

Explanation:

There is some info missing. I think this is the complete question.

Suppose a 250 mL flask is filled with 0.30 mol of N₂ and 0.70 mol of NO. The following reaction becomes possible:

N₂(g) +O₂(g) ⇄ 2 NO(g)

The equilibrium constant K for this reaction is 7.70 at the temperature of the flask. Calculate the equilibrium molarity of O₂. Round your answer to two decimal places.

Initially, there is no O₂, so the reaction can only proceed to the left to attain equilibrium. The initial concentrations of the other substances are:

[N₂] = 0.30 mol / 0.250 L = 1.2 M

[NO] = 0.70 mol / 0.250 L = 2.8 M

We can find the concentrations at equilibrium using an ICE Chart. We recognize 3 stages (Initial, Change, and Equilibrium) and complete each row with the concentration or change in the concentration.

N₂(g) +O₂(g) ⇄ 2 NO(g)

I 1.2 0 2.8

C +x +x -2x

E 1.2+x x 2.8 - 2x

The equilibrium constant (K) is:

$K=7.70=\frac{[NO]^{2}}{[N_{2}][O_{2}]} =\frac{(2.8-2x)^{2} }{(1.2+x).x}$

Solving for x, the positive one is x = 0.3601 M

[O₂] = 0.3601 M ≈ 0.36 M

7 0

3 years ago

The normal boiling point of a substance occurs when its vapor pressure is 1.00 atm, which means that at this temperature, the li

Sladkaya [172]

Answer:

See explanation below

Explanation:

For start, we need some values here to do this exercise.

In general, you can calculate the normal boiling point of any substance by using the Clausius Clapeyron equation which is the following:

ln(P2/P1) = -ΔHvap/R (1/T2 - 1/T1)

Where:

P1 and P2: pressure of the substance at T1 and T2.

ΔHvap: enthalpy of vaporization of the substance. In the case of bromine is 29.6 kJ/mol

R: constant gas. In this case is 8.3145 J/mol K

T1 and T2: temperature of the substance.

In order to calculate the normal boiling point, we will assign that value to T2, and the pressure would be 1 atm or 1.01x10^5 Pa

T1 and P1 would be temperature and pressure of this substance at any condition. For this example, I will take the fact that Bromine has 22000 Pa at 20 °C (or 293.15 K)

With this data, let's replace in the clausius Clapeyron equation:

ln(1.01x10^5 / 22000) = -29600/8.3145 (1/T2 - 1/293.15)

-1.5241 * 8.3145 / 29600 = (1/T2 - 1/293.15)

-4.281x10^-4 + 1/293.15 = 1/T2

T2 = 1 / 2.9831x10^-3

T2 = 335.22 or 62.07 °C

The real one is 59 °C so, the difference in the result may come with the values of P1 and T1 that may be not accurate.

7 0

3 years ago

4. Think of the solids and liquids that you encounter every day. In what ways are solids and liquids similar? In what ways are t

Taya2010 [7]

Answer:

They both are the same thing which is water but they are just in different forms.

Explanation:

A solid is water that is frozen and a liquid is just water.

3 0

2 years ago

What discovery led J.J. Thomson to decide that atoms were not indivisible, but are actually composed of smaller parts?

Zarrin [17]

Thomson used a beam of negatively charged particles. Using a beam of particles and detecting the scattering of the particles after they hit gold foil.

7 0

4 years ago

Sedimentary rocks are turned into metamorphic rocks by ______________.

abruzzese [7]

Answer:

When Sedimentary rocks are buried deep beneath the Earth's surface, great pressure and tremendous heat change these rocks into new rocks containing different minerals. These are Metamorphic rocks.

Explanation:

hope this helps

5 0

3 years ago