Answer:
25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.
Explanation:
The balanced reaction is:
2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O
By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:
- C₂H₂: 2 moles
- O₂: 5 moles
- CO₂: 4 moles
- H₂O: 2 moles
The molar mass of each compound is:
- C₂H₂: 26 g/mole
- O₂: 32 g/mole
- CO₂: 44 g/mole
- H₂O: 18 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- C₂H₂: 2 moles* 26 g/mole= 52 g
- O₂: 5 moles* 32 g/mole= 160 g
- CO₂: 4 moles* 44 g/mole= 176 g
- H₂O: 2 moles* 18 g/mole= 36 g
Then you can apply the following rule of three: if by stoichiometry 52 grams of C₂H₂ react with 160 grams of O₂, 8.15 grams of C₂H₂ react with how much mass of O₂?

mass of O₂= 25.08 grams
<u><em>25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.</em></u>
Explanation:
A Giant Gas Cloud. A star begins life as a large cloud of gas.
A Protostar Is a Baby Star.
The T-Tauri Phase.
Main Sequence Stars.
Expansion into Red Giant.
Fusion of Heavier Elements.
Supernovae and Planetary Nebulae.
Answer:
0.54 mole
Explanation:
CH3COOH CH3CH2OH CH3COOCH2CH3 H2O
Initial concentration 1.0 mole 1.0 mole 0 mole 1.0mol
Change - x - x + x + x
Equilibrium (1.0 - x) (1.0 - x) x (1.0 + x)
K = [CH3COOCH2CH3]*[H2O]/[CH3COOH]*[CH3CH2OH]
x*(1.0+x)/(1.0-x)(1.0-x) = 4.0
x+x²=4*(1-x)²
x+x² = 4(1² - 2x + x²)
x + x² = 4 - 8x + 4x²
4 - 8x + 4x²- x² - x= 0
3x² - 9x + 4 = 0
x=2.5 , x=0.54
2.5 mole of acid cannot be esterified, because there is only 1.0 mole of acid,
so answer is 0.54 mole.