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zhuklara [117]
3 years ago
11

Wind generally moves from:

Chemistry
2 answers:
marissa [1.9K]3 years ago
5 0

\huge{ \mathrm{  \underline{ Answer }}}\:  \:  ✓

D. Areas of high pressure to areas of low pressure.

_____________________________

_____________________________

\mathrm{ \#TeeNForeveR}

il63 [147K]3 years ago
4 0
D areas of high pressure to areas of low pressure :)
You might be interested in
Write equations to show whether the solubility of either of the following is affected by pH: (b) Hg₂(CN)₂.
nata0808 [166]

<u> Increasing pH will increase the solubility of the Hg2(CN)2 by shifting </u><u>equilibrium </u><u>to right side.</u>

What is the meaning of OH in chemistry?

The chemical group, ion, or radical OH that consists of one atom of hydrogen and one of oxygen and is neutral or negatively charged.

Hg2(CN)2 + 2OH-  ----> 2HgO(s) + 2HCN

adding OH- to the mercury(l) cyanide  will cause the formation of the solid HgO.

therefore increasing pH will increase the solubility of the Hg2(CN)2 by shifting equilibrium to right side.

Learn more about OH

brainly.com/question/2911201

#SPJ4

3 0
2 years ago
How many grams of CO2 are used when 6.0 g of O2 are produced? Express your answer with the appropriate units.
Ipatiy [6.2K]

Answer:

that is why co2 is in the power of 2ik

8 0
4 years ago
Stemscopedia
Alexeev081 [22]
What’s the question
7 0
3 years ago
Can I please Get Help with this question ‍♂️ ?
Nitella [24]

Answer:

Mg(NO4)2 is 180.3 g/mol

Explanation:

First find the substance formula.

Magnesium Nitrate.

Magnesium is a +2 charge.

Nitrate is a -1 charge.

So to balance the chemical formula,

We need 1 magnesium atom for every nitrate atom.

2(1) + 1(-2) = 0

So the substance formula is Mg(NO4)2.

Now find the molar mass of Mg(NO4)2.

Mg = 24.3 amu

N = 14.0 amu

O = 16.0 amu

They are three nitrogen and twelve oxygen atoms.

So you do this: 24.3 + 14.0(2) + 16.0(8) = 180.3 g/mol

So the molar is mass is 180.3 g/mol.

The final answer is Mg(NO4)2 is 180.3 g/mol

Hope it helped!

7 0
3 years ago
When 551. mg of a certain molecular compound X are dissolved in 100 g of benzonitrile (CH,CN), the freezing point of the solutio
arsen [322]

Answer:

1.12g/mol

Explanation:

The freezing point depression of a solvent for the addition of a solute follows the equation:

ΔT = Kf*m*i

<em>Where ΔT is change in temperature (Benzonitrile freezing point: -12.82°C; Freezing point solution: 13.4°C)</em>

<em>ΔT = 13.4°C - (-12.82) = 26.22°C</em>

<em>m is molality of the solution</em>

<em>Kf is freezing point depression constant of benzonitrile (5.35°Ckgmol⁻¹)</em>

<em>And i is Van't Hoff factor (1 for all solutes in benzonitrile)</em>

Replacing:

26.22°C = 5.35°Ckgmol⁻¹*m*1

4.90mol/kg = molality of the compound X

As the mass of the solvent is 100g = 0.100kg:

4.9mol/kg * 0.100kg = 0.490moles

There are 0.490 moles of X in 551mg = 0.551g, the molar mass (Ratio of grams and moles) is:

0.551g / 0.490mol

= 1.12g/mol

<em>This result has no sense but is the result by using the freezing point of the solution = 13.4°C. Has more sense a value of -13.4°C.</em>

5 0
3 years ago
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