Answer:
70.04 mL.
Explanation:
We can use the general law of ideal gas: V = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
If n is constant, and have two different values of V, P and T:
P₁V₁T₂ = P₂V₂T₁
P₁ = 795 torr, V₁ = 72.6 mL, T₁ = 23.0 °C + 273 = 296 K.
P₂ = 760 torr (standard pressure = 1 atm = 760 torr), V₂ = ??? mL,T₂ = 0.0 °C + 273 = 273 K (standard T).
∴ V₂ = P₁V₁T₂/P₂T₁ = (795 torr)(72.6 mL)(273 K)/(760 torr)(296 K) = 70.04 mL.
