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laiz [17]
3 years ago
8

Allison has $35 to spend at the pet store. She buys a large dog bowl for $15 and dog shampoo for $8. She wants to buy some dog b

ones that sell for $1.25 each.
a.) Write and solve an inequality to find the maximum number of dog bones, x, Allison can buy.
Mathematics
1 answer:
zysi [14]3 years ago
3 0

Answer:

She can buy 9 bones.

Step-by-step explanation: Because 9 times 1.25 equals $11.25 for bones.

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there are 3 times more students who play trumpet than the tuba. which expression represents the total number of trumpeters based
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The equation would look like:
3t
3 0
3 years ago
Read 2 more answers
WILL MARK YOU BRAINLIEST, PLEASE HELP!!!
lutik1710 [3]

Given:ABCD is a rhombus.

To prove:DE congruent to BE.

In rombus, we know opposite angle are equal.

so, angle DCB = angle BAD

SINCE, ANGLE DCB= BAD

SO, In triangle DCA

angle DCA=angle DAC

similarly, In triangle ABC

angle BAC=angle BCA

since angle BCD=angle BAD

Therefore, angle DAC =angle CAB

so, opposite sides of equal angle are always equal.

so,sides DC=BC

Now, In triangle DEC and in triangle BEC

1. .DC=BC (from above)............(S)

2ANGLE CED=ANGLE CEB (DC=BC)....(A)

3.CE=CE (common sides)(S)

Therefore,DE is congruent to BE (from S.A.S axiom)

7 0
3 years ago
two trains leave stations 210 miles apart at the same time and travel tword each other. one train at 85 miles per hour while the
hodyreva [135]

recall your d = rt, distance = rate * time.


let's say we have two trains, A and B, A is going at 85 mph and B at 65 mph.


they are 210 miles apart and moving toward each other, at some point they will meet, when that happens, the faster train A has covered say d miles, and the slower B has covered then the slack from 210 and d, namely 210 - d.


When both trains meet, A has covered more miles than B because A is faster, however the time both have been moving, is the same, say t hours.


\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ \textit{Train A}&d&85&t\\ \textit{Train B}&210-d&65&t \end{array}\\\\ \dotfill\\\\ \begin{cases} \boxed{d}=85t\\ 210-d=65t\\[-0.5em] \hrulefill\\ 210-\boxed{85t}=65t \end{cases} \\\\\\ 210=150t\implies \cfrac{210}{150}=t\implies \cfrac{7}{5}=t\implies \stackrel{\textit{one hour and 24 minutes}}{1\frac{2}{5}=t}

3 0
3 years ago
A statistics practitioner determined that the mean and standard deviation of a data set were 120 and 30, is respectively. What c
BartSMP [9]

Answer:

a) 68% of the observations lie between 90 and 150.

b) 95% of the observations lie between 60 and 180.

c) 99.7% of the observations lie between 30 and 210.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Standard deviation = 120

Mean = 30

a. 90 and 150

This is within 1 standard deviation of the mean.

By the Empirical Rule, 68% of the observations lie between 90 and 150.

b. 60 and 180

This is within 2 standard deviations of the mean.

By the Empirical Rule, 95% of the observations lie between 60 and 180.

c. 30 and 210

This is within 3 standard deviations of the mean.

By the Empirical Rule, 99.7% of the observations lie between 30 and 210.

4 0
3 years ago
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