Question

A train starts from rest and leaves Greenburg station with an acceleration of 1.20 meters per second2. How long does it take the train to travel a distance of 500 meters?

Answer 1

Answer:

Time, t = 28.87 seconds

Explanation:

Given the following data;

Acceleration = 1.20 m/s²

Distance = 500 meters

Initial velocity = 0 m/s

To find the time to cover the distance, we would use the second equation of motion;

$S = ut + \frac {1}{2}at^{2}$

Where;

S represents the displacement or height measured in meters.

u represents the initial velocity measured in meters per seconds.

t represents the time measured in seconds.

a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

$500 = 0*t + \frac {1}{2}*(1.2)*t^{2}$

$500 = 0 + 0.6*t^{2}$

$500 = 0.6t^{2}$

$t^{2} = \frac {500}{0.6}$

$t^{2} = 833.33$

Taking the square root of both sides, we have;

$t = \sqrt{833.33}$

Time, t = 28.87 seconds