Answer:
0.2 m/s^2
Explanation:
Maximum distance, h = 19.5 m
initial speed, u = 2.80 m/s
final speed, v = 0 m/s
Let the gravitational acceleration is a.
Use third equation of motion
a = 0.2 m/s^2
Thus the gravitational acceleration on the exoplanet is 0.2 m/s^2
Answer:
A) 10 m/s
Explanation:
We know that according to conservation of momentum,
m1v1 + m2v2 = m1u1 + m2u2 ..............(equation 1)
where m1 and m2 are masses of two bodies, v1 and v2 are initial velocity before collision and u1 and u2 are final velocities after collision respectively.
From the given data
If truck and car are two bodies
truck : m1 = 2000 Kg v1 = 5 m/s u1 = 0
car : m2 = 1000 kg v2 = 0 u2 = ?
final velocity of truck and initial velocity of car are static because the objects were at rest in the respective time.
substituting the values in equation 1, we get
(2000 x 5) + 0 = 0 + (1000 x u2)
u2 = x 5
= 10 m/s
Hence after collision, car moves at a velocity of 10 m/s
Flux through each of the six faces of the cube:
Explanation:
In this problem, a charge is placed at the center of the cube.
We can apply Gauss Law, which states that the flux through the surface of the cube is equal to the charge contained within the cube divided by the vacuum permittivity; mathematically:
where
is the charge
is the vacuum permittivity
Here we want to find the flux through each of the six faces of the cube.
By simmetry, we can say that the 6 faces are identical: therefore, the flux through each of them must be the same. This means that the flux through each faces is 1/6 of the total flux through the total surface, therefore:
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