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Leona [35]
2 years ago
12

A small toy school bus rear-ends a big toy school bus initially at rest. The bigger bus is several times heavier than the smalle

r one. Which of the following statements are true if the collision is elastic?
True / False / Maybe.
1. The two busses continue together at the same speed.
2. Mechanical energy is conserved.
3. The small bus exerts the same amount of force on the big bus as vice versa.
4. Momentum is conserved.
5. The small bus will go backwards.
Physics
1 answer:
Mars2501 [29]2 years ago
4 0

Answer:

Explanation:

1 . The two busses continue together at the same speed.

FALSE STATEMENT .

The small bus will have twice the velocity of bigger bus  velocity in the same direction . The bigger bus will continue with the same velocity .

2. Mechanical energy is conserved

TRUE STATEMENT.

3  The small bus exerts the same amount of force on the big bus as vice versa.

TRUE STATEMENT.

4.Momentum is conserved

TRUE STATEMENT.

5.The small bus will go backwards

FALSE STATEMENT .

The small bus will have twice the velocity of bigger bus  velocity in the same direction .

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.physics wave. Please don't dare to answer irrelevant
MAVERICK [17]

Answer:

1a) 857143 m

1b) 414 m

2a)

2b)

3) the medium of air has a wavelength of 0.334 m, the medium of water has a wavelength of 1.493 m, and the medium of 5.130 m.

Explanation:

Question 1a)

Given the velocity/speed, and frequency of the wave, the length can be calculated using these two quantites.

[ λ = v / f ] wavelength = <u>v</u>elocity of the wave / <u>f</u>requency of the wave in Hz.

Since 3 × 10^8 × ms^-1 is the velocity, and 350Hz is the frequency.

Anything to the negative power is reciprocated. i.e ms^-1 = m/s.

The wavelength is 300000000m/350Hz = 857142.8571428..... m ≈ 857143 m

Question 1b) Given that the frequency of the second wave in water is 1% of the first wave, and the speed of the second wave is 1450ms^-1

Therefore the second wave has a frequency of 1% of 3.5 = 350/100 Hz = 3.5 Hz

The wavelength is found using the same

formula: wavelength = 1450m/3.5Hz = 414.2857142857.... m ≈ 414 m

Question 2a)

Question 2b)

Question 3) Remember, the speed of sound of the medium = frequency of the medium × wavelength of the medium.

Therefore the wavelength of the medium = speed of sound of the medium / frequency of the medium. This has a similar correlation to the wavelength formula. We are given that all these mediums have a frequency of 1KHz = 1000Hz, where So the wavelength of each medium =

Question 4)

3 0
3 years ago
An alternating current is supplied to an electronic component with a rating that the voltage across it can never, even for an in
Vsevolod [243]

Answer:

A) V_{rms}=8\sqrt{2} V

Explanation:

Maximum voltage =V_{max}=16 V

Maximum voltage and rms voltage are related to each other by

V_{max}=V_{rms} \times \sqrt{2} \\V_{rms}=\frac{V_{max}}{ \sqrt{2}}\\V_{rms}=\frac{16}{\sqrt{2}} \\V_{rms}=8\sqrt{2} V

7 0
3 years ago
The magnetic field at the earth's surface can vary in response to solar activity. During one intense solar storm, the vertical c
Flauer [41]

Answer:

EMF = 33880 Volts

Explanation:

As per Faraday's law of Electromagnetic induction we know that

Rate of change in magnetic flux will induce EMF in the closed conducting loop

so we have

\phi = B.A

now we have

A = (110 \times 10^3)(110 \times 10^3)

A = 1.21 \times 10^{10}

now we have

\phi = B(1.21 \times 10^{10})

now the induced EMF through this loop is given as

EMF = (\frac{dB}{dt})(1.21 \times 10^{10})

EMF = (2.8 \times 10^{-6})(1.21 \times 10^{10})

EMF = 33880 Volts

5 0
3 years ago
A man is walking while riding a train. He says he is moving at 2 mph. A woman standing on a platform at a train station says the
Semenov [28]

The woman on the platform is correct because it is the pace of the man moving on the train not walking.

6 0
3 years ago
I'm stuck on question 3. Could anyone please explain it?
sergiy2304 [10]
Peak voltage is 2
period is 40ms
frequency = 1/period = 25Hz
5 0
2 years ago
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