Force = mass*acceleration so
3.6*2.5 =9 Newtons
The degree is 4678% to pass theough all membranes.
Answer:
(a). The strength of the magnetic field is 0.1933 T.
(b). The magnetic flux through the loop is zero.
Explanation:
Given that,
Radius = 11.9 cm
Magnetic flux
(a). We need to calculate the strength of the magnetic field
Using formula of magnetic flux
Put the value into the formula
(b). If the magnetic field is directed parallel to the plane of the loop,
We need to calculate the magnetic flux through the loop
Using formula of flux
Here,
Hence, (a). The strength of the magnetic field is 0.1933 T.
(b). The magnetic flux through the loop is zero.
Answer: Ok, first lest see out problem.
It says it's a Long cylindrical charge distribution, So you can ignore the border effects on the ends of the cylinder.
Also by the gauss law we know that E¨*2*pi*r*L = Q/ε0
where Q is the total charge inside our gaussian surface, that will be a cylinder of radius r and heaight L.
So Q= rho*volume= pi*r*r*L*rho
so replacing : E = (1/2)*r*rho/ε0
you may ask, ¿why dont use R on the solution?
since you are calculating the field inside the cylinder, and the charge density is uniform inside of it, you don't see the charge that is outside, and in your calculation actuali doesn't matter how much charge is outside your gaussian surface, so R does not have an effect on the calculation.
R would matter if in the problem they give you the total charge of the cylinder, so when you only have the charge of a smaller r radius cylinder, you will have a relation between r and R that describes how much charge density you are enclosing.
Answer:
1.97 × 10⁻¹⁸J
Explanation:
Charge of an electron q = -1.9 × 10⁻¹⁹C
Length of one side of the equilateral triangle at whose corners electrons are placed d = 3.5 × 10⁻¹⁰m
Coulomb constant k = 8.99 × 10⁹Nm²/C²
electrostatic potential = (3 kq²) / d
= (3 × 8.99 × 10⁹ × (-1.6 × 10⁻¹⁹)²) / 3.5 × 10⁻¹⁰
= 1.97 × 10¹⁸J