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alisha [4.7K]
3 years ago
14

What is the chemical formula for a compound that has 1 Nitrogen and 3 atoms of Hydrogen?

Chemistry
1 answer:
ad-work [718]3 years ago
7 0
Ammonia (NH3<span>) I believe~</span>
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Sergio [31]
Because in rock salt, the molecules are packed together and they take longer time to separate and dissolve. As for table salt the molecules are less packed together and take less time to dissolve. Think it like this. The more packed or tightly the substance/object is, the longer it will take for the object to dissolve. The less packed the object/substance is the faster it takes to dissolve. Hope this helped :)
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3 years ago
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7 0
3 years ago
Calculate the ph of a 0.60 m h2so3, solution that has the stepwise dissociation constants ka1 = 1.5 × 10-2 and 1.82 1.06 1.02 2.
Vsevolod [243]
Missing in your question Ka2 =6.3x10^-8
From this reaction:
 H2SO3 + H2O ↔ H3O+  + HSO3-
by using the ICE table :
                H2SO3     ↔    H3O     +    HSO3- 
intial         0.6                     0                  0
change     -X                      +X                +X
Equ         (0.6-X)                  X                   X

when Ka1 = [H3O+][HSO3-]/[H2SO3]
So by substitution:
1.5X10^-2 = (X*X) / (0.6-X) by solving this equation for X
∴ X = 0.088
∴[H2SO3] = 0.6 - 0.088 = 0.512
[HSO3-] = [H3O+] = 0.088

by using the ICE table 2:
                 HSO3-     ↔   H3O     +     SO3-
initial        0.088              0.088              0
change    -X                      +X                   +X
Equ         (0.088-X)          (0.088+X)          X

Ka2= [H3O+] [SO3-] / [HSO3-]
we can assume [HSO3-] =  0.088 as the value of Ka2 is very small
 6.3x10^-8 = (0.088+X)*X / 0.088
X^2 +0.088 X - 5.5x10^-9= 0 by solving this equation for X
∴X= 6.3x10^-8
∴[H3O+] = 0.088 + 6.3x10^-8
               = 0.088 m ( because X is so small)
∴PH= -㏒[H3O+]
       = -㏒ 0.088 = 1.06 
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RideAnS [48]

Answer: solid

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4) Formation of a solid product called as precipitate

Example of formation of precipitate or solid in chemical reaction:2AgNO_3(aq)+BaCl_2(aq)\rightarrow 2AgCl(s)+Ba(NO_3)_2(aq)


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