∠A and \angle B∠B are complementary angles. If m\angle A=(x+10)^{\circ}∠A=(x+10)
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15−2x−8−3x=−x−12+4x+43
now combine all the like terms on each side.
Add -2x and -3x
subtract 15 and -8....you subtract because the sign are different
now do the same for the other side
−5x+7=−x−12+4x+43
−5x+7=3x+31
bring the x value from the right side to the left side.
−5x+7−3x=31
combine like terms on left side
−8x+7=31
now move +7 to the right side which become..
−8x=−7+31
−8x=24
we will need to single out X by dividing
answer: X= -3
now combine all the like terms on each side.
Add -2x and -3x
subtract 15 and -8....you subtract because the sign are different
now do the same for the other side
−5x+7=−x−12+4x+43
−5x+7=3x+31
bring the x value from the right side to the left side.
−5x+7−3x=31
combine like terms on left side
−8x+7=31
now move +7 to the right side which become..
−8x=−7+31
−8x=24
we will need to single out X by dividing
answer: X= -3