All categories

3 years ago

Why does the moon orbit the earth as the earth orbits the sun?will give brainliest

1 answer:

6 0

As the Earth rotates, it also moves, or revolves, around the Sun. ... As the Earth orbits the Sun, the Moon orbits the Earth. The Moon's orbit lasts 27 1/2 days, but because the Earth keeps moving, it takes the Moon two extra days, 29 1/2, to come back to the same place in our sky.

You might be interested in

A particle of charge Q is fixed at the origin of an xy coordinate system. At t = 0 a particle (m = 0.959 g, q = 5.84 µC is locat

NemiM [27]

Answer:

$8.66\times 10^{-6}\ C$ or $8.66\ \mu C$ .

Explanation:

<u>Given:</u>

Charge on the particle at origin = Q.
Mass of the moving charged particle, $\rm m = 0.959\ g = 0.959\times 10^{-3}\ kg.$
Charge on the moving charged particle, $\rm q = 5.84\ \mu C = 5.84\times 10^{-6}\ C.$
Distance of the moving charged particle from first at t = 0 time, $\rm r=20.7\ cm = 0.207\ m.$
Speed of the moving particle, $\rm v = 47.9\ m/s.$

For the moving particle to circular motion, the electrostatic force between the two must be balanced by the centripetal force on the moving particle.

The electrostatic force on the moving particle due to the charge Q at origin is given by Coulomb's law as:

$\rm F_e = \dfrac{kqQ}{r^2}.$

where, $\rm k$ is the Coulomb's constant having value $\rm 9\times 10^9\ Nm^2/C^2.$

The centripetal force on the moving particle due to particle at origin is given as:

$\rm F_c = \dfrac{mv^2}{r}.$

For the two forces to be balanced,

$\rm F_e = F_c\\\dfrac{kqQ}{r^2}=\dfrac{mv^2}{r}\\\Rightarrow Q = \dfrac{mv^2}{r}\times \dfrac{r^2}{kq}\\=\dfrac{mv^2r}{kq}\\=\dfrac{(0.959\times 10^{-3})\times (47.9)^2\times (0.207)}{(9\times 10^9)\times (5.84\times 10^{-6})}\\=8.66\times 10^{-6}\ C\\=8.66\ \mu C.$

6 0

3 years ago

Fill in the blanks. The electrostatic force between two objects is proportional to the ____________________ of the distance ____

Shkiper50 [21]

Write an equation to calculate the force between two objects if the product of their charges is 10.0 × 10-4 C. (Note: Use the variable R for the distance between the charges.)

F = 900 ÷_________

6 0

3 years ago

Read 2 more answers

describe the motion of objects that are viewed from your reference frame both inside and outside while you travel inside a movin

V125BC [204]

Answer:

The objects outside the reference frame aren't moving. It appears this way since the vehicle you are inside is moving, but unless the objects are people, animals, or other vehicles, the objects aren't moving.

3 0

2 years ago

A place kicker must kick a football from a point 36.0 m (about 40 yards) from the goal. half the crowd hopes the ball will clear

trapecia [35]

<span>The ball clears by 11.79 meters Let's first determine the horizontal and vertical velocities of the ball. h = cos(50.0)*23.4 m/s = 0.642788 * 23.4 m/s = 15.04 m/s v = sin(50.0)*23.4 m/s = 0.766044 * 23.4 m/s = 17.93 m/s Now determine how many seconds it will take for the ball to get to the goal. t = 36.0 m / 15.04 m/s = 2.394 s The height the ball will be at time T is h = vT - 1/2 A T^2 where h = height of ball v = initial vertical velocity T = time A = acceleration due to gravity So plugging into the formula the known values h = vT - 1/2 A T^2 h = 17.93 m/s * 2.394 s - 1/2 9.8 m/s^2 (2.394 s)^2 h = 42.92 m - 4.9 m/s^2 * 5.731 s^2 h = 42.92 m - 28.0819 m h = 14.84 m Since 14.84 m is well above the crossbar's height of 3.05 m, the ball clears. It clears by 14.84 - 3.05 = 11.79 m</span>

4 0

3 years ago

What is the equation for an inelastic collision

abruzzese [7]

M1 v1 = (m1 + m2)v2.

All of the exponents should be lowered to the bottom right of the letters.

7 0

3 years ago

Why does the moon orbit the earth as the earth orbits the sun?will give brainliest​

Why does the moon orbit the earth as the earth orbits the sun?will give brainliest