<u>Answer:</u>
Perimeter = 20 units
x = 120°
<u>Step-by-step explanation:</u>
We are given a triangle ABC with known side lengths for all three sides and an inscribed circle.
We are to find the perimeter of triangle ABC and the value of x.
Perimeter of triangle ABC = 2 + 2 + 5 + 5 + 3 + 3 = 20 units
The kite shape at the end is a quadrilateral which has a sum of angles of 360 degrees.
Two out of four angles are right angles and one is 60 so we can find the value of x.
x = 360 - (90 + 90 + 60) = 120°
Join the centre O to the chord (let it be MN) & let OH be the perpendicular to the chord
OH bisects MN into 2 equal parts (each one is x/2)
OMH is a right triangle with one side =8, the second leg =x/2 & the hypotenuse = 12 (Radius)
Apply Pythagoras:
12² = 8² +(x/2)² ==>144=64 + x²/4 ==> x²=4(144-64) =320
x²=320==> x=√320 =17.88 ≈17.9
Answer:
no solution
Step-by-step explanation:
Any of the "-slope" or "slope-" formulas for a line cannot be used when the slope is undefined.
The equation of the desired line is x = -2. It cannot be put into the form y = ....
Basically you get the volume first:
10 times 10 times 50
Which is 5,000
And we're given the cans volume already:
9.42
So what we do now is divided the area by the cans for our answer:
5,000/9.42
Which is 530.785563
So Sean can stack 530 cans of beans in his shelf.
(when rounding is is 531 cans)
