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3 years ago

Select the correct answer. Which electromagnetic waves have the highest frequencies in the electromagnetic spectrum?

Physics

1 answer:

Law Incorporation [45]3 years ago

4 0

Answer:

Your answer would be C, Radio waves.

Explanation:

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In an old-fashioned amusement park ride, passengers stand inside a 3.0-m-tall, 5.0-m-diameter hollow steel cylinder with their b

lesya692 [45]

Answer:2.55 rad/s

Explanation:

Given

Diameter of ride=5 m

radius(r)=2.5 m

Static friction coefficient range=0.60-1

Here Frictional force will balance weight

And limiting frictional force is provided by Centripetal force

$f=\mu N=\mu m\omega ^2\cdot r$

weight of object=mg

Equating two

f=mg

$\mu m\omega ^2\cdot r=mg$

$\omega ^2=\frac{g}{\mu r}$

$\omega =\sqrt{\frac{g}{\mu r}}$

$\omega =2.55 rad/sec$

8 0

3 years ago

A marble is placed at the bottom of a semi-spherical bowl, as shown in the figure. The marble is then displaced from the bottom

Andrew [12]

Answer:

It is D

Explanation:

8 0

2 years ago

A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a rope that goes over an ideal pulley. If the masses are

irga5000 [103]

Answer:

The time taken will be 0.553 seconds.

Explanation:

We should start off by finding the force exerted by the rope on the 3kg weight in this case.

Weight of 5kg mass = 5 * 9.81 = 49.05 N

Weight of 3kg mass = 3 * 9.81 = 29.43 N

The force acting upward on the 3kg mass will equal the weight of the 5kg mass. Thus the resultant force acting on the 3kg mass is:

Total force = 49.05 - 29.43 = 19.62 N (upwards)

We can now find the acceleration:

F = m * a

19.62 = 3 * a

a = 6.54 m/s^2

We now use the following equation of motion to get the time taken to travel 1 meter:

$s=u*t+\frac{1}{2} (a*t^2)$

$1=0*t+\frac{1}{2} (6.54*t^2)$

t = 0.553 seconds

4 0

3 years ago

A pendulum takes 4 seconds to make one complete swing. A man walks 100m in a straight line while the pendulum makes 20 complete

irina [24]

The average velocity of the man is determined as 1.25 m/s.

<h3>Average velocity of the man</h3>

Total distance traveled by the man = 100 m

If 1 complete cycle = 4 s

20 complete cycle = ?

= 20 x 4 s

= 80 s

Average velocity = total distance/total time

Average velocity = 100 m/80 s

Average velocity = 1.25 m/s

Thus, the average velocity of the man is determined as 1.25 m/s.

Learn more about average velocity here: brainly.com/question/6504879

#SPJ1

4 0

1 year ago

A uniform metre rod of 5 metre length is suspended horizontally by two strings P and Q.Pis attached 0.8 metre from one end and Q

denpristay [2]

Answer:

The tension in string P is 25 N, while that of Q is 85 N.

Explanation:

Considering the conditions for equilibrium,

i. Total upward force = Total downward force

$T_{P}$ + $T_{Q}$ = 110 N

ii. Taking moment about P,

clockwise moment = anticlockwise moment

110 × (2.5 - 0.8) = $T_{Q}$ × (3 - 0.8)

110 × 1.7 = $T_{Q}$ × 2.2

187 = 2.2 $T_{Q}$

$T_{Q}$ = $\frac{187}{2.2}$

$T_{Q}$ = 85 N

From the first condition,

$T_{P}$ + $T_{Q}$ = 110 N

$T_{P}$ + 85 N = 110 N

$T_{P}$ = 110 - 85

$T_{P}$ 25 N

Therefore, the tension in string P is 25 N while that of Q is 85 N.

5 0

2 years ago