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vladimir2022 [97]
4 years ago
8

Select the correct answer. Which electromagnetic waves have the highest frequencies in the electromagnetic spectrum?

Physics
1 answer:
Law Incorporation [45]4 years ago
4 0

Answer:

Your answer would be C, Radio waves.

Explanation:

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11Alexandr11 [23.1K]

Answer:

D thermal energy moves from the marshmallow to your fingers as you touch the marshmallow

Explanation:

Conduction is the movement of thermal energy without the actual movement of the particles of a body. They particles only collide with each other and transfer energy in the process while maintaining their mean positions.

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NEED HELP NOW DUE TODAY Which of these statements is most likely correct about Newton's law on gravity? (2 points)
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3 years ago
Q6) A speed skater moving to the left across frictionless ice at 8.0 m/s hits a 5.0-m-wide patch of rough ice. She slows steadil
77julia77 [94]

Answer:

-2.8 m/s²

Explanation:

Acceleration: This can be defined as the rate of change of velocity The S. I unit of acceleration is m/s²

Using the equation of motion,

v² = u² + 2as................... Equation 1

Where v = Final velocity, u = initial velocity, a = acceleration, s = distance,

Given: v = 6.0 m/s, u = 8.0 m/s, s = 5.0 m.

Substituting into equation 1

6² = 8²+2(a)5

36 = 64 + 10a

10a = 36-64

10a = -28

10a/10 = -28/10

a = -2.8 m/s²

Note: a is negative because because the skater decelerate on the rough ice

Hence the magnitude of her acceleration is  = -2.8 m/s²

6 0
3 years ago
A bucket of water is being raised from a well using a rope. If the bucket of water has a mass of 6.2 kg, how much force (in N) m
Sholpan [36]

Answer:

6.2N force

Explanation:

According to Newton's second law of motion, force is equal to the product of the mass of a body and its acceleration. Mathematically,

Force = mass × acceleration

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acceleration of the bucket = 1m/s²

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= 6.2N

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3 years ago
A box is initially sliding across a frictionless floor toward a spring which is attached to a wall. the box hits the end of the
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U= \frac{1}{2}kx^2
where k is the spring's constant and x is the displacement with respect to the relaxed position of the spring.

The work done by the spring is the negative of the potential energy difference between the final and initial condition of the spring:
W=-\Delta U =  \frac{1}{2}kx_i^2 -  \frac{1}{2}kx_f^2

In our problem, initially the spring is uncompressed, so x_i=0. Therefore, the work done by the spring when it is compressed until x_f is
W=- \frac{1}{2}kx_f^2
And this value is actually negative, because the box is responsible for the spring's compression, so the work is done by the box.
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