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3 years ago

Which statement describes how rock characteristics affect rates of weathering?

Chemistry

1 answer:

Leya [2.2K]3 years ago

5 0

Rocks with GAPS AND CRACKS weather more quickly than rocks with smooth surfaces. Rocks without minerals more quickly than rocks MADE UP of many minerals.

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based on the article what are some of the advantages that can be given by radio frequency and microwaves

bonufazy [111]

Answer:

higher data rates are

Explanation:

transmitted

as the bandwidth

is more

more antenna gain is possible

6 0

3 years ago

Which of the following buffer systems would you use if you wanted to prepare a solution having a pH of approximately 9.5?Which o

zalisa [80]

Answer:

b. 0,08M NH₄⁺ / 0,12M NH₃

Explanation:

The buffers are:

a. 0,08M H₂PO₄⁻ / 0,12M HPO₄²⁻

b. 0,08M NH₄⁺ / 0,12M NH₃

It is possible to find out the pH of a buffer using Henderson-Hasselbalch formula:

pH = pka + log₁₀ [A⁻] / [HA] (1)

Where A⁻ is the conjugate base of the weak acid, HA.

a. For the system H₂PO₄⁻ / HPO₄²⁻ pka is 7,198. Replacing in (1)

pH = 7,198 + log₁₀ [0,12] / [0,08]

pH = 7,37

That means this buffer system don't have a pH of approximately 9,5

b. For the system NH₄⁺ / NH₃ pka is 9,3. Replacing in (1)

pH = 9,3 + log₁₀ [0,12] / [0,08]

pH = 9,50

That means this buffer system is the buffer you need to use.

I hope it helps!

7 0

4 years ago

A gas is collected in a 34.3L container at a temperature of 31.5°C. Later, the container has a volume of 29.2L, a temperature of

goldenfox [79]

Answer:

108 kPa

Step-by-step explanation:

To solve this problem, we can use the Combined Gas Laws:

p₁V₁/T₁ = p₂V₂/T₂ Multiply each side by T₁

p₁V₁ = p₂V₂ × T₁/T₂ Divide each side by V₁

p₁ = p₂ × V₂/V₁ × T₁/T₂

Data:

p₁ = ?; V₁ = 34.3 L; T₁ = 31.5 °C

p₂ = 122.2 kPa; V₂ = 29.2 L; T₂ = 21.0 °C

Calculations:

(a) Convert temperatures to kelvins

T₁ = (31.5 + 273.15) K = 304.65 K

T₂ = (21.0 + 273.15) K = 294.15 K

(b) Calculate the pressure

p₁ = 122.2 kPa × (29.2/34.3) × (304.65/294.15)

= 122.2 kPa × 0.8542 × 1.0357

= 108 kPa

4 0

3 years ago

How many grams of oxygen are required to burn 13.5 g of acetylene

Vinil7 [7]

Answer:

41.54 grams of oxygen are required to burn 13.5 g of acetylene

Explanation:

The balanced reaction is:

2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

C₂H₂: 2 moles
O₂: 5 moles
CO₂: 4 moles
H₂O: 2 moles

Being the molar mass of the compounds:

C₂H₂: 26 g/mole
O₂: 32 g/mole
CO₂: 44 g/mole
H₂O: 18 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

C₂H₂: 2 moles* 26 g/mole= 52 grams
O₂: 5 moles* 32 g/mole= 160 grams
CO₂: 4 moles* 44 g/mole= 176 grams
H₂O: 2 moles* 18 g/mole= 36 grams

You can apply the following rule of three: if by stoichiometry 52 grams of acetylene react with 160 grams of oxygen, 13.5 grams of acetylene react with how much mass of oxygen?

$mass of oxygen=\frac{13.5 grams of acetylene*160 grams of oxygen}{52 grams of acetylene}$

mass of oxygen= 41.54 grams

41.54 grams of oxygen are required to burn 13.5 g of acetylene

8 0

3 years ago

Write the balanced chemical equation for the Haber-Bosch process, that is, the combination of nitrogen and hydrogen to form ammo

RoseWind [281]

The balanced chemical equation for the Haber-Bosch process is N₂(g) + 3H₂(g) → 2NH₃(g). The Haber-Bosch process played a significant role in boosting agriculture back in the day. It paved the way for the industrial production of ammonia which is used in the manufacture of fertilizers. The process involves reacting atmospheric N₂ with H₂ using a metal catalyst under high temperature and pressure.

6 0

3 years ago

Read 2 more answers