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3 years ago

Is the flow of power reversible in a worm and wheel gear

1 answer:

8 0

The flow of power cannot be reversed since the slider could not move the worm gears. Since the input has one continuous tooth and the output has not teeth there is no gear ratio and no change in torque and speed.

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BlackZzzverrR [31]

Answer:

what are is ethiopia cultural ?

7 0

2 years ago

A closed, rigid tank is lled with a gas modeled as an ideal gas, initially at 27°C and a gage pressure of 300 kPa. The gas is he

sergejj [24]

Answer:

T₂ =93.77 °C

Explanation:

Initial temperature ,T₁ =27°C= 273 +27 = 300 K

We know that

Absolute pressure = Gauge pressure + Atmospheric pressure

Initial pressure ,P₁ = 300+1=301 kPa

Final pressure ,P₂= 367+1 = 368 kPa

Lets take temperature=T₂

We know that ,If the volume of the gas is constant ,then we can say that

$\dfrac{P_2}{P_1}=\dfrac{T_2}{T_1}$

${T_2}=T_1\times \dfrac{P_2}{P_1}$

Now by putting the values in the above equation we get

${T_2}=300\times \dfrac{368}{301}\ K$

The temperature in °C

T₂ = 366.77 - 273 °C

T₂ =93.77 °C

8 0

3 years ago

Which of the following is not an electronic device ?

PolarNik [594]

Answer:

Explanation:

it's does not transmit any energy

6 0

2 years ago

U 4. Find 2 bridges in the US and answer the following:

Zarrin [17]

Answer:

Im guessing this is for CEA for PLTW, if so look up the exact assignment number and look at online examples of the exact same assignment.

Explanation:

6 0

3 years ago

You want a potof water to boil at 105 celcius. How heavy a

ankoles [38]

Answer:

35.7 kg lid we put

Explanation:

given data

temperature = 105 celcius

diameter = 15 cm

Patm = 101 kPa

to find out

How heavy a lid should you put

solution

we know Psaturated from table for temperature is 105 celcius is

Psat = 120.8 kPa

area will be here

area = $\frac{\pi }{4} d^2$ ..................1

here d is diameter

put the value in equation 1

area = $\frac{\pi }{4} 0.15^2$

area = 0.01767 m²

so net force is

Fnet = ( Psat - Patm ) × area

Fnet = ( 120.8 - 101 ) × 0.01767

Fnet = 0.3498 KN = 350 N

we know

Fnet = mg

mass = $\frac{Fnet}{g}$

mass = $\frac{350}{9.8}$

mass = 35.7 kg

so 35.7 kg lid we put

3 0

3 years ago