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murzikaleks [220]
3 years ago
6

A design that either partially or wholly integrates the bodywork

Engineering
1 answer:
Yakvenalex [24]3 years ago
6 0

Answer:

body-on-frame design.

:))

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Why does the ring on saturn spin
spayn [35]

Answer: THERE IS NO GRAVITY IN SPACE SO ROCKS SPIN

Explanation:

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2 years ago
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What type of car engine is best for cold weather.
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Answer:Antifreeze/coolant

Explanation: keeps your engine cool in warm weather and keeps it from freezing up in the winter. A 50-50 mix of full strength coolant and water generally protects to around -30 degrees Fahrenheit. Make sure you check with the supplier or your owner's manual for the correct formulation

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2 years ago
By adding "-once", one can form the noun form of the word "organize" is that true or false?​
denpristay [2]

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<h2>False </h2>

Explanation:

The noun form of organize is just adding letter r

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2 years ago
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The high electrical conductivity of copper is an important design factor that helps improve the energy efficiency of electric mo
ludmilkaskok [199]

Answer:

B

Explanation:

This is a two sample t-test and not a matched pair t-test

null hypothesis(H0) will be that mean energy consumed by copper rotor motors is greater than or equal to mean energy consumed by aluminium rotor motors

alternate hypothesis(H1) will be that mean energy consumed by copper rotor motors is less than or equal to mean energy consumed by aluminium rotor motors.

So, option D is rejected

The hypothesis will not compare mean of differences of values of energy consumed by copper rotor motor and aluminium rotor motor.

Option A and C are also rejected

5 0
3 years ago
A 1 turn coil carries has a radius of 9.8 cm and a magnetic moment of 6.2 X 10 -2 Am 2. What is the current through the coil?
Alexus [3.1K]

Answer:

The current through the coil is 2.05 A

Explanation:

Given;

number of turns of the coil, N = 1

radius of the coil, r = 9.8 cm = 0.098 m

magnetic moment of the coil, P = 6.2 x 10⁻² A m²

The magnetic moment is given by;

P = IA

Where;

I is the current through the coil

A is area of the coil = πr² = π(0.098)² = 0.03018 m²

The current through the coil is given by;

I = P / A

I = (6.2 x 10⁻² ) / (0.03018)

I = 2.05 A

Therefore, the current through the coil is 2.05 A

6 0
3 years ago
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