Answer:
The total contraction of the bar is 1.228 mm
Explanation:
The parameters given are;
Length of aluminium bar = 600 mm
Diameter of aluminium bar = 40 mm
Diameter of hole in aluminium bar = 30 mm
Length of hole = 100 mm
Modulus of elasticity of aluminium = 85 GN/m²
Applied compressive load = 180 kN

Where:
δ = Total contraction of the bar
A₁ for the hole section = 
A₂ for the solid section = 
L₁ = 100 mm
L₂ = 600 - 100 = 500 mm

The total contraction of the bar = 1.228 mm.
Below is the program to separate odd and even numbers
<u>Explanation</u>:
<u>L1:</u>
mov ah,00
mov al,[BX]
mov dl,al
div dh
cmp ah,00
je EVEN1
mov [DI],dl
add OddAdd,dl
INC DI
INC BX
Loop L1
jmp CAL
<u>EVEN1:</u>
mov [SI],dl
add Even Add,dl
INC SI
INC BX
Loop L1
<u>CAL: </u>
mov ax,0000
mov bx,0000
mov al,OddAdd
mov bl,EvenAdd
MOV ax,4C00h
int 21h
end
The above program separates odd and even numbers from the array using 8086 microprocessor. It has odd numbers in 2000h and even numbers in 3000h.
The radius of the specimen is 60 mm
<u>Explanation:</u>
Given-
Length, L = 60 mm
Elongated length, l = 10.8 mm
Load, F = 50,000 N
radius, r = ?
We are supposed to calculate the radius of a cylindrical brass specimen in order to produce an elongation of 10.8 mm when a load of 50,000 N is applied. It is necessary to compute the strain corresponding to this
elongation using Equation:
ε = Δl / l₀
ε = 10.8 / 60
ε = 0.18
We know,
σ = F / A
Where A = πr²
According to the stress-strain curve of brass alloy,
σ = 440 MPa
Thus,

Therefore, the radius of the specimen is 60 mm
Answer:
a)A constant volume process is called isochoric process.
b)Yes
c)Work =0
Explanation:
Isochoric process:
A constant volume process is called isochoric process.
In constant volume process work done on the system or work done by the system will remain zero .Because we know that work done give as
work = PΔV
Where P is pressure and ΔV is the change in volume.
For constant volume process ΔV = 0⇒ Work =0
Yes heat transfer can be take place in isochoric process.Because we know that temperature difference leads to transfer of heat.
Given that
Initial P=10 MPa
Final pressure =15 MPa
Volume = 100 L
Here volume of gas is constant so the work work done will be zero.