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3 years ago

Calculate the number of ways to arrange 9 books of different tittles on a book

Mathematics

2 answers:

Alex Ar [27]3 years ago

6 0

Answer:

D good luck :) also have a great day

Elina [12.6K]3 years ago

3 0

I thought it was B because you can arrange it on that one book 9 times. and then you can change the base book nine times which would give you nine more different combinations per book

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eric is 70 inches tall pablo is as half as tall as eric annette is 5.25 inches taller than pablo how tall is annette

Kazeer [188]

Answer:

$40.25$ inches

Step-by-step explanation:

Following what the problem mentions:

"eric is 70 inches tall"

$Eric=70in$

"pablo is as half as tall as eric"

$pablo=\frac{Eric}{2}$

$pablo=\frac{70in}{2}=35in$

and "annette is 5.25 inches taller than pablo"

$annete=pablo+5.25in$

$annette=35in+5.25in =40.45in$

Annette is 40.25 inches tall

7 0

3 years ago

Give the domain and range.

ale4655 [162]

Answer:

a. domain: {0, 2, 4}, range: {2, 6, 10}

Step-by-step explanation:

The given diagram depicts a function.

Let us define function:

A function is a mapping of inputs to output.

The left ones are the input of the function while the right side values are the output of the function.

The domain of the function is the set of values that are given as input to the function while the outputs are called range.

so, in the given question

The domain is: {0,2,4} and the range is: {2,6,10}

So, Option A is correct ..

7 0

3 years ago

Am I dealing with harmonic stuff (trig)?

pochemuha

You just need to solve for when $y=0$ :

$\dfrac{\cos8t-9\sin8t}4=0\implies\cos8t-9\sin8t=0$

$\implies\cos8t=9\sin8t$

$\implies\dfrac19=\dfrac{\sin8t}{\cos8t}=\tan8t$

$\implies8t=\tan^{-1}\dfrac19+n\pi$

$\implies t=\dfrac18\tan^{-1}\dfrac19+\dfrac{n\pi}8$

where $n$ is any integer. We only care about when $0\le t\le1$ , which happens for $n\in\{0,1,2\}$ .

$t=\dfrac18\tan^{-1}\dfrac19\approx0.01$

$t=\dfrac18\tan^{-1}\dfrac19+\dfrac\pi8\approx0.41$

$t=\dfrac18\tan^{-1}\dfrac19+\dfrac\pi4\approx0.80$

8 0

3 years ago

Given that P = (-5, 5) and Q = (-13, 10), find the component form and magnitude of 2 vector PQ.

Brut [27]

Define unit vectors along the x-axis and the y-axis as $\hat{i} , \, \hat{j}$ respectively.

Then the vector from P to Q is
$\vec{PQ} = (-13+5)\hat{i} + (10-5)\hat{j} = -8\hat{i} + 5\hat{j}$
In component form, the vector PQ is (-8,5).

The magnitude of vector PQ is
√[(-8)² + 5²] = √(89) = 9.434

Answer:
The vector PQ is (-8, 5) and its magnitude is √89 (or 9.434).

4 0

3 years ago

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Why is it important to line up the decimal points?

jolli1 [7]

The operations must take account of the place values of individual digits in the numbers.

Please give brainliest :)))

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3 years ago

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