What is the concentration (m) of sodium ions in 4.57 l of a 2.35 m na3p solution?
2 answers:
Answer:
7.05 M
Explanation:
- An equation can be written:
Na₃P → 3Na⁺ + P⁻³
- The formula for concentration (M) is the number of moles divided by the volume in L:
C = n / V
With the concentration and volume given by the problem, we know the number of moles of Na₃P, then with that number we can calculate the moles of Na⁺:
4.57 L * 2.35 M = 10.7395 mol Na₃P
10.7395 mol Na₃P * = 32.2185 mol Na⁺.
Concentration of Na⁺ = mol Na⁺ / V
[Na⁺] = 32.2185 mol Na⁺ / 4.57 L = 7.05 M
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<u>Answer:</u> The value of is 0.136 and is reactant favored.
<u>Explanation:</u>
Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as
For the chemical reaction between carbon monoxide and hydrogen follows the equation:
The expression for the is given as:
We are given:
Putting values in above equation, we get:
There are 3 conditions:
- When
; the reaction is product favored.
- When
; the reaction is reactant favored.
- When
; the reaction is in equilibrium.
For the given reaction, the value of is less than 1. Thus, the reaction is reactant favored.
Hence, the value of is 0.136 and is reactant favored.