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katrin2010 [14]
3 years ago
5

What is the concentration (m) of sodium ions in 4.57 l of a 2.35 m na3p solution?

Chemistry
2 answers:
White raven [17]3 years ago
7 0

Answer:

7.05 M

Explanation:

  • An equation can be written:

Na₃P → 3Na⁺ + P⁻³

  • The formula for concentration (M) is the number of moles divided by the volume in L:

C = n / V

With the concentration and volume given by the problem, we know the number of moles of Na₃P, then with that number we can calculate the moles of Na⁺:

4.57 L * 2.35 M = 10.7395 mol Na₃P

10.7395 mol Na₃P * \frac{3molNa^{+}}{1molNa_{3}P} = 32.2185 mol Na⁺.

Concentration of Na⁺ = mol Na⁺ / V

[Na⁺] = 32.2185 mol Na⁺ / 4.57 L = 7.05 M

Leokris [45]3 years ago
5 0
Answer: 1.03 x 10^25 ions Na
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