What is the concentration (m) of sodium ions in 4.57 l of a 2.35 m na3p solution?
2 answers:
Answer:
7.05 M
Explanation:
- An equation can be written:
Na₃P → 3Na⁺ + P⁻³
- The formula for concentration (M) is the number of moles divided by the volume in L:
C = n / V
With the concentration and volume given by the problem, we know the number of moles of Na₃P, then with that number we can calculate the moles of Na⁺:
4.57 L * 2.35 M = 10.7395 mol Na₃P
10.7395 mol Na₃P * = 32.2185 mol Na⁺.
Concentration of Na⁺ = mol Na⁺ / V
[Na⁺] = 32.2185 mol Na⁺ / 4.57 L = 7.05 M
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Answer:
109.09°C
Explanation:
Given that:
the capacity of the cooling car system = 5.6 gal
volume of solute = volume of the water; since a 50/50 blend of engine coolant and water (by volume) is used.
∴
Afterwards, the mass of the solute and the mass of the water can be determined as shown below:
mass of solute =
On the other hand; the mass of water =
Molarity =
=
= 17.757 m
≅ 17.76 m
∴ the boiling point of the solution is calculated using the boiling‑point elevation constant for water and the Molarity.
where,
= 0.512 °C/m
= 100°C + 17.56 × 0.512
= 109.09 °C