Question

What is the concentration (m) of sodium ions in 4.57 l of a 2.35 m na3p solution?

Answer 1

Answer:

7.05 M

Explanation:

• An equation can be written:

Na₃P → 3Na⁺ + P⁻³

• The formula for concentration (M) is the number of moles divided by the volume in L:

C = n / V

With the concentration and volume given by the problem, we know the number of moles of Na₃P, then with that number we can calculate the moles of Na⁺:

4.57 L * 2.35 M = 10.7395 mol Na₃P

10.7395 mol Na₃P * $\frac{3molNa^{+}}{1molNa_{3}P}$ = 32.2185 mol Na⁺.

Concentration of Na⁺ = mol Na⁺ / V

[Na⁺] = 32.2185 mol Na⁺ / 4.57 L = 7.05 M

Answer 2

Answer: 1.03 x 10^25 ions Na