Answer:24.31
Explanation:Contribution made by isotope of mass 23.99= 23.99×78.99=1894.97
Contribution made by isotope of mass 24.99=24.99×10.00=249.9
Contribution made by isotope of mass 25.98=25.98×11.01=286.04
Total contribution=1894.97+249.9+286.04=2430.91
Average mass=2430.91÷100
=24.31
Well you are at a 86% so t<span>his is considered a "B" grade on an average grade scale. If you take 50 points we would need to know the Total point you could have got in that class to be able to see how much a percent was the assignment work and then take that percentage of the assignment and subtract it from the 86% to see where on the scale you would fall in after the assignment points were taken off. Hope this helps :)
</span>
A saturated solution is one in which no more solute is able to dissolve in a given solvent at a particular temperature. Some amount of the solute is left undissolved in the solution.
Unsaturated solution has solute in lower proportions than required to form a saturated solution.
Supersaturated solution has solute in amounts greater than a saturated solution.
We can take the help of solubility curve in order to find out the amount of a salt required to prepare a saturated solution of that salt at a particular temperature.
The solubility of KI at 10
is 136 g/ 100 mL water
The solubility of
at
is 21 g/100 mL water.
The solubility of
at
is 80 g/100 mL water.
The solubility of NaCl at
is 38 g/ 100 mL water.
So the correct answer will be KI, as it would need 136 g KI / 100 mL water to form a saturated solution at
.So, if we have 80g KI/ 100mL water it would be an unsaturated solution.
Answer:
286.55K
Explanation:
To convert to kelvin , add 237 .15

<u>Answer:</u> The value of
is 0.136 and is reactant favored.
<u>Explanation:</u>
Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as 
For the chemical reaction between carbon monoxide and hydrogen follows the equation:

The expression for the
is given as:
![K_{c}=\frac{[NH_3]^2}{[N_2][H_2]^3}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5BH_2%5D%5E3%7D)
We are given:
![[NH_3]=0.25M](https://tex.z-dn.net/?f=%5BNH_3%5D%3D0.25M)
![[H_2]=0.75M](https://tex.z-dn.net/?f=%5BH_2%5D%3D0.75M)
![[N_2]=1.1M](https://tex.z-dn.net/?f=%5BN_2%5D%3D1.1M)
Putting values in above equation, we get:


There are 3 conditions:
- When
; the reaction is product favored. - When
; the reaction is reactant favored. - When
; the reaction is in equilibrium.
For the given reaction, the value of
is less than 1. Thus, the reaction is reactant favored.
Hence, the value of
is 0.136 and is reactant favored.