The absolute pressure in psia being measured is; 27.228 psia
<h3>What is the absolute Pressure?</h3>
Formula for absolute Pressure is;
Absolute pressure = Atmospheric pressure + Gauge pressure
P_{abs} = P_{atm} + P_g
We are given;
P_atm = 29.86 (in Hg) = 14.666 psia
Density of mercury at 70 °F; ρ = 13.543 g/cm³
Mercury Manometer reading; h = 25.62 in
Acceleration due to gravity; g = 32.243 ft/s²
Gauge pressure of the mercury = ρgh = 13.543 * 25.62 * 32.243
When we multiply and covert to psia gives; P_g = 12.562 psia
Thus;
P_abs = 14.666 + 12.562
P_abs = 27.228 psia
Read more about Absolute Pressure at; brainly.com/question/17200230
Answer:B
Explanation:
Given
For motor A
Characteristic life(r)=4100 hr
MTTF=4650 hrs
shape factor(B )=0.8
For motor B
Characteristic life(r)=336 hr
MTTF=300 hr
Shape Factor (B)=3
Reliability for 100 hours



For B


B is better for 100 hours
(b)For 750 hours


So here B is more Reliable.
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5.85 psig
Using a specific gravity of 0.75 as an average for red\automobile gasoline.
Water at standard conditions (60 degF) is 2.31 feet = 1 psig
80/2.31 then multiply x .75 to compensate for specific gravity of water being 1.0
Hello, because there is not a circuit I'll explain the voltage divider and make an exercise, this way you can solve the problem using the method described here.
Answer with explanation:
A voltage divider uses the voltage distribution among components to find a voltage in a specific element of the circuit. If we have a source V1 connected to impedances Z1 and Z2 in series, we can use a voltage divider to find the voltage across Z1 or Z2 base on their value and the input voltage.
VZ1 = V1*Z1/(Z1+Z2)
VZ2 = V1*Z2/(Z1+Z2)
In the image, to find the voltage Vo across R2 we apply the following equation: Vo = (V1*R2)/(R1+R2).
To solve the exercise in the other image, we need to apply a voltage divider twice:
In-circuit 1 we are asked to find the voltage VAB that falls on R2 and R3 (the same voltage for both resistances because are in parallel), to do so we use a voltage divider using V1, R1 and RT where RT is the equivalent resistance RT = R2//R3 + R4, therefore, for circuit two VAC = (V1*R1)/(R1+RT). After finding VAC we apply voltage divider again to find VAB, see circuit 3, to do so we apply VAB = (VAC*R2//R3)/(R2//R3 + R4) = (VAC*R2//R3)/(RT)