Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer:
Step-by-step explanation: What you want to do is find the grid point of each for example D is -4,-4 than you want to add those like B is 8,-6 so you would do -4+-8 and -4+-6 so you get 2,-10 for the distance of DB
The shortest possible height of tower is 24 cm.
Tim used 4 blue blocks and his brother used 3 green blocks.
Step-by-step explanation:
Given,
Height of blue block = 6 cm
Height of green block = 8 cm
We will take least common multiple to find the shortest possible height.
6 = 2*3
8 = 2*2*2
LCM = 2*2*2*3 = 24 cm
The shortest possible height of tower is 24 cm.
Number of blue blocks used =
Number of green blocks used =
Tim used 4 blue blocks and his brother used 3 green blocks.
Keywords: LCM, multiplication
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