Answer:
The mass of the object is approximately 70.79 kilograms
Explanation:
We use Newton's second law to solve this problem. This law states that the net force on an object equals the product of its mass times the acceleration:
![F_{net}=m\,a](https://tex.z-dn.net/?f=F_%7Bnet%7D%3Dm%5C%2Ca)
Therefore, for this case, since the net force on the object and its acceleration are given, we can use the equation above to solve for the unknown mass:
To develop this problem, it is necessary to apply the concepts related to Faraday's law and Magnetic Flow, which is defined as the change that the magnetic field has in a given area. In other words
![\Phi = BA Cos\theta](https://tex.z-dn.net/?f=%5CPhi%20%3D%20BA%20Cos%5Ctheta)
Where
B= Magnetic Field
A = Area
Angle between magnetic field lines and normal to the area
The differentiation of this value allows us to obtain in turn the induced emf or electromotive force.
In this case we have that the flat loop of wire is perpendicular to the magnetic field, therefore the angle is 0 degrees, since its magnetic field acts parallel to the area:
0 then our expression can be written as
![\Phi = BA](https://tex.z-dn.net/?f=%5CPhi%20%3D%20BA)
From the same value of the electromotive force we have to
![\epsilon = -\frac{d\Phi}{dt}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%20-%5Cfrac%7Bd%5CPhi%7D%7Bdt%7D)
Replacing we have
![\epsilon = -A\frac{B}{dt}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%20-A%5Cfrac%7BB%7D%7Bdt%7D)
Replacing with our values we have that
![\epsilon = -(7.9*10^{-4}m)\frac{(3.5-0.5)}{0.1}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%20-%287.9%2A10%5E%7B-4%7Dm%29%5Cfrac%7B%283.5-0.5%29%7D%7B0.1%7D)
![\epsilon = -0.0237V](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%20-0.0237V)
Therefore the magnitude of the induced emf in the loop is 0.0237V
On the other hand we have that the current by Ohm's Law can be defined as
![I = \frac{\epsilon}{R}](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7B%5Cepsilon%7D%7BR%7D)
For the given value of the resistance and the previously found potential we have to
![I = \frac{0.237}{1.3}](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7B0.237%7D%7B1.3%7D)
![I= 0.0182A](https://tex.z-dn.net/?f=I%3D%200.0182A)
1. The answer ur question is A.<span>observe the phase of the moon each night until a full moon can be seen.
2.The answer 2 ur secound question is </span><span>B.The Moons position relative to the sun and earth as it revolves around sun.</span>
As we can see that the boy is moving his hand up and down while producing the wave in the string.
Here we can see that the source of disturbance or source of wave here in this example is the boy who is holding the string at one end.
So here the motion of the hand of boy is representing the motion of medium molecules in the medium always
So here the disturbance of wave is travelling in the string to the right direction while if we see the direction of medium molecules then it is moving perpendicular to the string i.e. up and down
This type of wave is known as transverse waves in which medium molecules moves perpendicular to the direction of wave
That completely depends on what characteristic you use to sort them.
You could list the planets in order of their mass, diameter, density,
rotation period, surface temperature, orbital eccentricity, inclination
to the ecliptic, surface reflectivity, etc. Each sorting criterion would
give you a different list.
In the order of the length of the semi-major-axis of each planet's orbit,
the sequence, from smallest to largest, is ...
Mercury
Venus
Earth
Mars
Jupiter
Saturn
Uranus
Neptune
the former planet Pluto.