Answer:
a pea!
Explanation:
Calculate the mass of a 1250 mL solution of CaCl2 at 0.75 M
1 answer:
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C. the square root of 2gh
Explanation:
The square root of 2gh is equivalent to Torricelli's law in the equation.
given expression:
m v² = mgh
to find v, we make it the subject of the expression:
*multiply both sides of the equation by 2:
2 x( m v² )= 2 (mgh)
mv² = 2mgh
*cancel the mass, m appearing on both sides:
v² = 2gh
* find the square root of both side
v = √2gh
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Answer:
The mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882
Explanation:
We are given that
Aqueous solution that contains 22.9% NaOH by mass means
22.9 g NaOH in 100 g solution.
Mass of NaOH(WB)=22.9 g
Mass of water =100-22.9=77.1
Na=23
O=16
H=1.01
Molar mass of NaOH(MB)=23+16+1.01=40.01
Number of moles =
Using the formula
Number of moles of NaOH
Molar mass of water=16+2(1.01)=18.02g
Number of moles of water
Now, mole fraction of NaOH
=
=0.882
Hence, the mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882