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vivado [14]
3 years ago
12

What is the area of the composite figure?

Mathematics
1 answer:
sasho [114]3 years ago
8 0

Answer:

59.5

Step-by-step explanation:

(7x7) + (7x3)/2

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What is the point-slope equation of a line if the slope is 3 and it passes through the point (-9, 2
Art [367]

Answer:

The point-slope equation of the line is y - 2 = 3(x + 9)

Step-by-step explanation:

The form of the point-slope equation is y - y1 = m(x - x1), where

  • m is the slope of the line
  • (x1, y1) is a point on the line

∵ The slope of a line is 3

∴ m = 3

∵ The line passes through point (-9, 2)

∵ x1 = -9

∴ y1 = 2

→ Substitute the values of m, x1, and y1 in the point-slope form

∵ y - y1 = m(x - x1)

∴ y - 2 = 3(x - (-9))

→ Remember (-)(-) = (+)

∴ y - 2 = 3(x + 9)

∴ The point-slope equation of the line is y - 2 = 3(x + 9)

6 0
3 years ago
PLEASE HELP 30 POINTS Wendell is looking over some data regarding the strength, measured in Pascals (Pa), of some building mater
jarptica [38.1K]

Logarithmic functions and exponential functions are inverse and opposite of one another

The logarithmic function is y = \log_2(x), and the length at 8 pascals is 3 units

<h3>How to determine the logarithmic function</h3>

The exponential function is given as:

f(x) = 2^x

Express f(x) as y

y = 2^x

Swap the positions of x and y

x = 2^y

Take the logarithm of both sides

\log(x) = \log(2^y)

Apply the rule of logarithm

\log(x) = y\log(2)

Divide both sides by log(2)

y = \frac{\log(x)}{\log(2)}

Apply the change of base rule of logarithm

y = \log_2(x)

When the strength is 8 pascals, we have:

y = \log_2(8)

Express 8 as 2^3

y = \log_2(2^3)

So, we have:

y =3 \log_2(2)

Evaluate log 2 base 2

y =3

Hence, the logarithmic function is y = \log_2(x), and the length at 8 pascals is 3 units

Read more about logarithmic and exponential functions at:

brainly.com/question/11464095

7 0
2 years ago
What is the decimal multiplier to decrease by 3.4%?
olga nikolaevna [1]

Answer:

3.4%

=3.4/100

=0.034

Now,

1-0.034

0.966

0.966 is the multiplier

Step-by-step explanation:

8 0
3 years ago
Find the critical value of x2 based on the given information H1 &gt;3.5 n=14 a=0.05
egoroff_w [7]

Answer:

The degrees of freedom are given by:

df = n-1=14-1=13

The significance level is \alpha=0.05 and then the critical value can be founded in th chi square table we need a quantile that accumulates 0.05 of the area in the right tail of the distribution and for this case is:

\chi^2_{\alpha}= 22.362

And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.

Step-by-step explanation:

We have the followign system of hypothesis:

Null hypothesis: \sigma^2 \leq 3.5

Alternative hypothesis: \sigma^2 >3.5

The degrees of freedom are given by:

df = n-1=14-1=13

The significance level is \alpha=0.05 and then the critical value can be founded in th chi square table we need a quantile that accumulates 0.05 of the area in the right tail of the distribution and for this case is:

\chi^2_{\alpha}= 22.362

And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.

4 0
3 years ago
Given the graph of a function f. Identify the function by name. Then Graph, state domain &amp; range in set notation:A) f(x) +2B
WARRIOR [948]

The function in the graph has the name of square function.

The domain of a function is all values of x the function can have. The domain of this function is all real numbers:

\mleft\lbrace x\in\R\mright\rbrace

The range of a function is all values of y the function can have. The range of this function is all positive numbers, including zero:

\mleft\lbrace y\in\R\mright|y\ge0\}

In order to graph f(x) + 2, we just need to translate the graph 2 units up. To find the new points, we need to increase all y-coordinates by 2:

(-2, 6), (-1, 3), (0, 2), (1, 3), (2, 6)

Domain: {x ∈ ℝ}

Range: {y ∈ ℝ | y ≥ 2}

Then, in order to graph f(x) - 2, we just need to translate the graph 2 units down. To find the new points, we need to decrease all y-coordinates by 2:

(-2, 2), (-1, -1), (0, -2), (1, -1), (2, 2)

Domain: {x ∈ ℝ}

Range: {y ∈ ℝ | y ≥ -2}

4 0
1 year ago
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