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maw [93]
3 years ago
9

Consider a projectile launched with an initial velocity of v0 = 120 ft/s, inclined at an angle, θ with the horizontal. Let us as

sume that the projectile lands on a spot that is at a height h = 10 feet, raised in elevation from its launch point. For this entire problem, you can neglect drag.
a) Determine an expression for the horizontal range R as a function of time. Here, range represents the total horizontal distance traveled from launch point to point of landing. Your answer will be in terms of initial velocity v0, time t, height h and acceleration due to gravity, g. At this point, do not substitute any of the numerical values yet.
b) Determine the time taken to achieve the maximum possible range, R. Think about maxima and minima from calculus when solving this part of the problem.
c) Once you have determined the time from part (b), substitute the numerical values for the terms and obtain the actual time in seconds. Then, determine the initial launch angle, θ (also called the angle of attack), such that the projectile achieves the maximum possible horizontal range.
d) What is the numerical value of this maximum R (based on your calculations from parts (b) and (d)).
e) Determine the velocity at the peak of the trajectory of the projectile.
f) Determine the time taken for the projectile to reach its peak height on its trajectory.
g) Determine the peak height reached by the projectile.
Physics
1 answer:
Natali [406]3 years ago
4 0

Answer:

How to find the maximum height of a projectile?

if α = 90°, then the formula simplifies to: hmax = h + V₀² / (2 * g) and the time of flight is the longest. ...

if α = 45°, then the equation may be written as: ...

if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that's the case of horizontal projectile motion.

Explanation:

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What types of changes in motion cause acceleration?
xxTIMURxx [149]

Answer:

Change in velocity and direction over a specific period of time.

Explanation:

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate the acceleration of an object.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

a = \frac{v  -  u}{t}

Where,

a is acceleration measured in ms^{-2}

v and u is final and initial velocity respectively, measured in ms^{-1}

t is time measured in seconds.

Hence, the types of changes in motion that cause acceleration is a change in velocity and direction over a specific period of time.

6 0
3 years ago
shows a conical pendulum, in which the bob (the small object at the lower end of the cord) moves in a horizontal circle at const
Contact [7]

Answer:

a) T=0.40 N

b) T=1.9 s

Explanation:

Let's find the radius of the circumference first. We know that bob follows a circular path of circumference 0.94 m, it means that the perimeter is 0.94 m.

The perimeter of a circunference is:

P=2\pi r=0.94

r=\frac{0.94}{2\pi}=0.15 m

Now, we need to find the angle of the pendulum from vertical.

tan(\alpha)=\frac{r}{L}=\frac{0.15}{0.90}=0.17

\alpha=9.44 ^{\circ}

Let's apply Newton's second law to find the tension.

\sum F=ma_{c}=m\omega^{2}r

We use centripetal acceleration here, because we have a circular motion.

The vertical equation of motion will be:

Tcos(\alpha)=mg (1)

The horizontal equation of motion will be:

Tsin(\alpha)=m\omega^{2}r (2)

a) We can find T usinf the equation (1):

T=\frac {mg}{cos(\alpha)}=\frac{0.04*9.81}{cos(9.44)}=0.40 N

We can find the angular velocity (ω) from the equation (2):

\omega=\sqrt{\frac{Tsin(\alpha)}{mr}}=3.31 rad/s

b) We know that the period is T=2π/ω, therefore:

T=\frac{2\pi}{\omega}=\frac{2\pi}{3.31}=1.9 s

I hope it helps you!

8 0
2 years ago
The law of conservation of mass states that mass can never be created or destroyed, only changed. true or faulse
Aleksandr-060686 [28]

Answer:

true

Explanation:

The law of conservation of mass states that in a chemical reaction mass is neither created nor destroyed. For example, the carbon atom in coal becomes carbon dioxide when it is burned. The carbon atom changes from a solid structure to a gas but its mass does not change.

7 0
3 years ago
Describe the three major layers of the earth including temperature thickness of chemical composition
Elena L [17]
The three main layers are the core, the mantle, and the crust. The core is divided into two parts, the liquid outer core, and the solid inner core. Together it is 3450 km thick. The mantle is 2100 km thick, and the crust is 35-70 km thick. Hope I helped!
3 0
3 years ago
If an object is accelerating at 4 m/s^2 and has a mass of 8 kg, what is the net
Salsk061 [2.6K]

Answer:

The force applied is 32 N

Explanation:

F = ma

F = 8 × 4

F = 32 N

7 0
3 years ago
Read 2 more answers
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