Answer:
Double and triple covalent bonds occur when four or six electrons are shared between two atoms, and they are indicated in Lewis structures by drawing two or three lines connecting one atom to another
Explanation:
13.5g
Explanation:
Given parameters:
Mass of Na = 10g
Mass of O₂ = 10g
Unknown:
Mass of products formed = ?
Balanced equation = ?
Solution:
The balanced chemical equation is shown below:
4Na + O₂ ⇒ 2Na₂O
In any reaction, the specie in short supply determines the extent of the reaction.
This reaction is not an exclusion. We need to first determine the specie in short supply and use it to estimate the amount of product since we have a 100% yield which signifies that all was used up.
let us convert to moles;
Number of moles of Na =
= 0.435mole
Number of moles of O₂ =
= 0.313mole
From the given equation;
4 moles of Na requires 1 mole of O₂;
0.435 moles of Na will require
= 0.11 moles
But the given amount O₂ is 0.313, this is an excess of 0.313 - 0.11 = 0.203moles
We see that Na is the limiting reagent;
4 moles of Na gives 2 mole of Na₂O
0.435 moles of Na will give
= 0.22 moles
Mass of Na₂O = number of moles x molar mass = 62 x 0.22 = 13.5g
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Answer:
Option NH 3 is the correct answer.
Explanation:
A molecule which has hydrogen bonding will have the highest boiling point. So, out of the given options only NH 3 will have hydrogen bonding.
Whereas in CHCI 3 there will be dipole-dipole interactions and no hydrogen bonding within the molecule.
In OF 2 and C 6H 6, there will be dipole-dipole interaction in both the molecules.
Thus, we can conclude that NH 3 will have the highest boiling point.
In a redox reaction an electron is lost by the reducing agent
We are given with two amounts of the reactants and is asked to determine which of the two is the limiting reactant. In this case, we just have to convert the mass of HCL first and divide by 4. The answer is 0.33. Hence, HCl is used up first. The grams of Cl2 produced is 23.43 grams