Answer:
B. There is no solution.
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
- Solving systems of equations by graphing
Step-by-step explanation:
<u>Step 1: Define systems</u>
y = x + 9x + 5
y = -x + 11x + 29
<u>Step 2: Simplify systems</u>
y = 10x + 5
y = 10x + 29
<u>Step 3: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 10x + 5 = 10x + 29
- Subtract 10x on both sides: 5 ≠ 29
Here we see that 5 does not equal 29.
∴ The systems has no solutions.
<u>Step 4: Graph systems</u>
<em>Check the solution set (if applicable).</em>
We see that the 2 lines are parallel and will never intersect. Therefore, this proves that our systems has no solution.
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Answer:
Step-by-step explanation:
Using either the critical value rule or the p-value rule, a conclusion can be drawn at a level of significance (alpha)
The null hypothesis: u = hypothesized mean
Alternative hypothesis: u > u0 or u < u0 for a one tailed test
Alternative hypothesis for a two tailed test: u =/ u0
To draw a conclusion by failing to reject the null hypothesis as stated then: using critical value
Observed z score > critical z score for both the one and two tailed test.
Or using p value:
P-value > alpha for a one tailed test
P-value > alpha/2 for a two tailed test
Thus, if a one-sided null hypothesis for a single mean cannot be rejected at a given significance level, then the corresponding two-sided null hypothesis will also not be rejected at the same significance level.
Yes c would work best here