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Shkiper50 [21]
3 years ago
10

2. How many orbitals are in the following sublevels?

Chemistry
1 answer:
stich3 [128]3 years ago
6 0
This answer would be a
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Convert 4 x 10^-3 dL to cm^3 <br><br> Please give the work and the answer in scientific notation.
Serhud [2]

4 x  10^{-3 in dL will be 4 x  10^{-1}  cm^3

<h3>Conversion from dL to cm^3</h3>

Recall that:

Deci = 10^{-1}

Centi = 10^{-2}

Thus, 1 dl = 100 ml

This means that converting from dl to  cm^3 requires multiplying by 10^2.

Applying this principle, 4 x 10^{-3 in dL to  cm^3 will be:

4 x 10^{-3 x  10^2 cm^3 = 4 x  10^{-1}  cm^3

Therefore,  4 x 10^{-3 dl will be 4 x  10^{-1}  cm^3

More on volume conversion can be found here:

#SPJ1

3 0
2 years ago
Please help need to turn in
ohaa [14]

Answer:

2. d

3. i

4. e

5. j

6. g

7. a

8. f

9. b

Explanation:

do a few searches when you have time to deepen understanding!

8 0
2 years ago
Read 2 more answers
How do I do these chemistry equations?
Katen [24]
I don’t even know I just need to answer a question sorry
3 0
3 years ago
2KI + Pb(NO3)2 → 2KNO3 + PbI2 Determine how many moles of KNO3 are created if 0.03 moles of KI are completely consumed.
ElenaW [278]
2:2 so the same proportion 
0,03

6 0
3 years ago
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A balloon contains 0.950 mol of nitrogen gas and has a volume of 25.5 L. How many grams of N2 should be released from the balloo
kirill [66]
Answer:
Mass released = 8.6 g
Explanation:
Given data:
Initial number of moles nitrogen= 0.950 mol
Initial volume = 25.5 L
Final mass of nitrogen released = ?
Final volume = 17.3 L
Solution:
Formula:
V₁/n₁ = V₂/n₂
25.5 L / 0.950 mol = 17.3 L/n₂
n₂ = 17.3 L× 0.950 mol/25.5 L
n₂ = 16.435 L.mol /25.5 L
n₂ = 0.644 mol
Initial mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.950 mol × 28 g/mol
Mass = 26.6 g
Final mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.644 mol × 28 g/mol
Mass = 18.0 g
Mass released = initial mass - final mass
Mass released = 26.6 g - 18.0 g
Mass released = 8.6 g
3 0
3 years ago
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