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olga nikolaevna [1]
2 years ago
10

I need help with this someone help

Chemistry
1 answer:
allochka39001 [22]2 years ago
6 0

Answer:

1. Element is Ca

2. 20 electrons

3. 2 valence electrons

4. 4 energy levels

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What does X represent for this transmutation?
Dimas [21]

Answer:

 24He

Explanation:

When a nuclide is bombarded with alpha particles, we notice an increase in its mass and charge since an alpha particle has a mass of four and a charge of +2. recall that nuclear equations must be balanced. That is, the masses and charges on the left hand six and the right hand side of the nuclear reaction equation must be exactly the same.

Looking at the nuclear reaction at hand, the total mass on the left hand side has to be 246 while the total charge on the left hand side of the equation will be 98. Coming over to the right hand side, the total masses are also found to be the same as a neutron with no charge and a mass of 1 is produced. Hence the nuclear reaction equation is balanced when an alpha particle (helium nucleus) is substituted for X in the equation.

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3 years ago
Please answer this for me shehsh
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Answer:

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Explanation:

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3 years ago
Among the following which solution is the most acidic?
Vika [28.1K]

i think it c i dont know if im right tho.

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3 years ago
Explain what happens to the particles in a substance during a physical change.
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When a physical change occurs, the arrangement of particles within the substance may change, but the atoms in the molecules remain bonded together.
4 0
3 years ago
Read 2 more answers
The standard free-energy change for this reaction in the direction written is 23.8 kJ/mol. The concentrationsof the three interm
Natali [406]

Answer: The actual free-energy change for the reaction  -8.64 kJ/mol.

Explanation:

The given reaction is as follows.

  Fructose 1,6-bisphosphate \rightleftharpoons Glyceraldehyde 3-phosphate + DHAP

For the given reaction, \Delta G^{o} is 23.8 kJ/mol.

As we know that,

       \Delta G = \Delta G^{o} + RT ln Q

Here,    R = 8.314 J/mol K,       T = 37^{o} C

                                                    = (37 + 273) K

                                                    = 310.15 K

Fructose 1,6-bisphosphate = 1.4 \times 10^{-5} M

Glyceraldehyde 3-phosphate = 3 \times 10^{-6} M

DHAP = 1.6 \times 10^{-5} M

Expression for reaction quotient of this reaction is as follows.

    Reaction quotient = \frac{[DHAP][\text{glyceraldehyde 3-phosphate}]}{[/text{Fructose 1,6-bisphosphate}]}

        Q = \frac{1.6 \times 10^{-5} \times 3 \times 10^{-6}}{1.4 \times 10^{-5}}

            = 3.428 \times 10^{-6}

Now, we will calculate the value of \Delta G as follows.

          \Delta G = \Delta G^{o} + RT ln Q

                      = 23800 + 8.314 \times 310.15 \times ln(3.428 \times 10^{-6})

                      = -8647.73 J/mol

                      = -8.64 kJ/mol

Thus, we can conclude that the actual free-energy change for the reaction  -8.64 kJ/mol.

7 0
3 years ago
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