2 years ago

1.protozoo ore ?

Physics

1 answer:

erik [133]2 years ago

4 0

Answer:

Explanation:

amembers of the group protocista

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A field measuring 12 meters by 16 meters is to have a brick paver walkway installed all around it, increasing the total area to

kolezko [41]

Answer:

1.5 m

Explanation:

Length. L = 12 m

Width, W = 16 m

Area, A = 12 x 16 = 192 m^2

Let the width of pavement be d.

The new length, L' = 12 + 2d

the new width, W' = 16 + 2d

New Area, A' = L' x W' = (12 + 2d)(16 + 2d) = 192 + 56 d + 4d^2

Difference in area = A' - A

285 = 192 + 56 d + 4d^2 - 192

93 = 56 d + 4d^2

4d^2 + 56 d - 93 = 0

$d = \frac{-56\pm \sqrt{56^{2}+4\times 4\times 93}}{8}$

$d=\frac{-56\pm 87.72}{8}$ \

d = 1.5 m

Thus, the width of the pavement is 1.5 m.

6 0

4 years ago

A transport truck pulls on a trailer with a force of 600N [E]. The trailer pulls on the transport truck with a force

kramer

These forces form a force pair. Use Newton's third law, and you see that the trailer pulls back at with the same force. The answer is d.

6 0

3 years ago

Read 2 more answers

You can enter compound units that are combinations of other units that are multiplied together.Torque can be calculated by multi

Paraphin [41]

Answer:

3.0 x 10¹ Nm

Explanation:

Torque = F x r

Where F is force applied and r is perpendicular distance from pivot point . r

is also called lever arm

Here F = 15 N and r = 2.0 m

Torque

= 15 N X 2.0 m

= 3.0 10¹ Nm.

4 0

3 years ago

Fill in the blank

aliina [53]

Answer:

hypothesis

Explanation:

8 0

3 years ago

It is correct to say that impulse is equal toA) momentum.B) the change in momentum.C) the force multiplied by the distance the f

goldenfox [79]

Answer:

B) the change in momentum

Explanation:

Impulse is defined as the product between the force exerted on an object (F) and the contact time ( $\Delta t$ )

$I=F \Delta t$

Using Newton's second law (F = ma), we can rewrite the force as product of mass (m) and acceleration (a):

$I=(ma) \Delta t$

However, the acceleration is the ratio between the change in velocity ( $\Delta v$ ) and the contact time ( $\Delta t$ ): $a=\frac{\Delta v}{\Delta t}$ , so the previous equation becomes

$I=m \frac{\Delta v}{\Delta t}\Delta t$

And by simplifying $\Delta t$ ,

$I=m \Delta v$

which corresponds to the change in momentum of the object.

8 0

3 years ago