Answer:
The point C is 12.68 km away from the point A on a bearing of S23.23°W.
Step-by-step explanation:
Given that AB is 50 km and BC is 40 km as shown in the figure.
From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|
=|50 sin 80° - 40 cos 20°|=11.65 km
The length of y-component of AC = |AB cos 80° - BC sin 20°|
=|50 cos 80° - 40 sin 20°|= 5 km
tan
= 5/11.65
=23.23°
AC=
km
Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.
Here, use the app photomath.
Answer:
b = 104
Step-by-step explanation:
Slope is expressed as;
m = y2-y1/x2-x1
14 = b - 6/5-(-2)
14 = b - 6/5+2
14 = b-6/7
Cross multiply
b-6 = 14 * 7
b - 6 = 98
b = 98 + 6
b = 104
Answer:

Step-by-step explanation:
The given expression is :

It can be solved as follows :

So, the solution of the given expression is equal to
.