1. 100.67
2. 168.55
3. 2.747
So I’m not sure if 2 or 3 are right sorry
This follows the law of conservation of momentum. Momentum is the product of mass and velocity of object.
Momentum = mass(m) x velocity(v)
law of conservation of momentum means that the total momentum of system before the collision of 2 objects is equal to the total momentum after the collision
Before the collision total momentum
= m1v1 + m2v2
m1 = 2 kg
v1 = 2 m/s
m2 = 6 kg
v2 = 0 m/s
substituting the values in the equation
total momentum before = (2 kg x 2 m/s) + (6 kg x 0 m/s)
total momentum = 4 kgm/s
after the collision the 2 objects stick together and have a common velocity
total momentum after the collision = (6 kg + 2 kg)x V = 8V
V = speed of the conglomerate particle
since total momentum before is equal to total momentum after
8V = 4
V = 2 m/s
speed of conglomerate particle is 2 m/s
B. elements and compounds
The line segment is describe as a line which joints two points. The word segment is denotes the end points of the line. The symbol of the line segment is AB. This symbol is indicating a line from the point A to the point B.
- Generally, the line segment has two endpoints. The meeting point of two line segments is called as the vertex and also it is considered as a common endpoint on the other hand line is a straight path of points that goes on and on in two directions
- Vertex is a point where two rays meet OR where the sides of a polygon meet OR the point where three or more edges of a solid figure meet and the angle is Formed by two rays that have the same endpoint
To know more about line segment visit :
brainly.com/question/25727583
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Answer:
The nuclear charge increases from boron to carbon, but there is no additional shielding( that is no additional shells).
Explanation:
First of all, we must know the electron configuration of carbon and boron.
Boron- 1s2 2s2 2p1
Carbon- 1s2 2s2 2p2
Moving from boron to carbon, the effective nuclear charge increases without a corresponding increase in the number of shells. Remember that shielding increases with increase in the number of intervening shells between the outermost electron and the nucleus. Since there isn't an increase in shells, boron experience a lower screening effect.
From
Zeff= Z- S
The Z for carbon is 6 while for boron is 5 even though both have the same number of screening electron S(4 screening electrons). Hence it is expected the Zeff(effective nuclear charge) for boron will be less than that of carbon.
