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SOVA2 [1]
3 years ago
8

What is the difference between electric potential and potential energy explain briefly

Physics
1 answer:
jarptica [38.1K]3 years ago
6 0

Answer:

<h2>is this a Gifted Graduation?</h2>

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Can someone help pls
Illusion [34]
Qs 1: m = 1/2*KE*V^2

qs 2: 6,223.39 kg
8 0
3 years ago
What is mean by the value of universal gravitional constant is 6.67×10^-11​
aev [14]

Answer:

According to the gravitational law of Isaac Newton, "the gravitational force between any two objects is proportional to the product of the objects’ masses and inversely proportional to the square of the separation between their centers".

Therefore gravitational constant is the proportionality constant used in Newton’s Law of Universal Gravitation, and is commonly denoted by G. It is expressed as:

                                                 F= Gm1m2/r2

Another scientist Cavendish was able to measure the gravitational force and the value of the proportionality constant. It is expressed as G = 6.673×10-11 N m2 kg-2.

8 0
3 years ago
A hockey puck moving at 28 m/s is caught by an 80,00 kg man who was at
zimovet [89]

Answer:

A

Explanation:

all the work is in the attached file :D

8 0
4 years ago
The momentum of an object depends on what two forces
mr_godi [17]

The Linear momentum depends on

1) Mass

2) Linear Velocity

The angular momentum depends on

1) Inertia

2) Rotational velocity

7 0
3 years ago
awhite billiard ball with mass mw = 1.47 kg is moving directly to the right with a speed of v = 3.01 m/s and collides elasticall
pochemuha

Answer:

speed of white ball is 1.13 m/s and speed of black ball is 2.78 m/s

initial kinetic energy = final kinetic energy

KE = 6.66 J

Explanation:

Since there is no external force on the system of two balls so here total momentum of two balls initially must be equal to the total momentum of two balls after collision

So we will have

momentum conservation along x direction

m_1v_{1i} + m_2v_{2i} = m_1v_{1x} + m_2v_{2x}

now plug in all values in it

1.47 \times 3.01 + 0 = 1.47 v_1cos68 + 1.47 v_2cos22

so we have

3.01 = 0.375v_1 + 0.927v_2

similarly in Y direction we have

m_1v_{1i} + m_2v_{2i} = m_1v_{1y} + m_2v_{2y}

now plug in all values in it

0 + 0 = 1.47 v_1sin68 - 1.47 v_2sin22

so we have

0 = 0.927v_1 - 0.375v_2

v_2 = 2.47 v_1

now from 1st equation we have

3.01 = 0.375 v_1 + 0.927(2.47 v_1)

v_1 = 1.13 m/s

v_2 = 2.78 m/s

so speed of white ball is 1.13 m/s and speed of black ball is 2.78 m/s

Also we know that since this is an elastic collision so here kinetic energy is always conserved to

initial kinetic energy = final kinetic energy

KE = \frac{1}{2}(1.47)(3.01^2)

KE = 6.66 J

5 0
4 years ago
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