Potassium can be a component of the cream.
<h3>Why does potassium show white-purple flame when burned?</h3>
An element's presence can be determined using a flame test. The potassium in cream of tartar is what gives it its white-purple color.
Low ionization enthalpy elements allow the flame to display color. Due to low ionization enthalpy, when an element is heated, its valence electrons are quickly excited to higher orbits and emit light as they return to their original orbit. Salts of potassium emit a white-purple color when ignited. The cream of tartar's chemical formula is KC₄H₅O₆.
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Answer:
P4Se3
Explanation:
Applying the Law of Conservation of Mass:
(133 mg total) - (45.8 mg P) = 87.2 mg Se
Dividing by the molar mass,
Phosphorus:-(45.8 mg P) / (30.97376 g P/mol) = 1.4786 mmol P
Selenium:-(87.2 mg Se) / (78.96 g Se/mol) = 1.1044 mmol Se
Divide by the smaller number of millimoles:
(1.4786 mmol P) / 1.1044 mmol = 1.339
(1.1044 mmol Se) / 1.1044 mmol = 1.000
multiply by 3, to get a whole number interger. then round to the nearest whole numbers to find the empirical formula.
Therefore the empirical formula is P4Se3
Answer:
A) 2.27 grams of tungsten trioxide must be needed to prepare 1.80 g of tungsten.
B)To prepare 1.80 g of tungsten we will need 0.0587 grams of hydrogen gas.
Explanation:
A) Mass of tungsten prepared = 1.80 g
Moles of tungsten =
According to reaction, 1 mol of tungsten is obtained from 1 mole of tungsten trioxide.
Then 0.009783 moles of tungsten will be obtained from:
of tungsten trioxide
Mass of 0.009783 moles of tungsten trioxide :
0.009783 mol × 231.8 g/mol = 2.27 g
2.27 grams of tungsten trioxide must be needed to prepare 1.80 g of tungsten.
B) According to reaction,1 mol of tungsten is produced by 3 moles of hydrogen gas
Then 0.009783 moles of tungsten are produced by :
Mass of 0.02935 moles of hydrogen gas:
0.02935 mol × 2 g/mol =0.0587 g
To prepare 1.80 g of tungsten we will need 0.0587 grams of hydrogen gas.
Answer:
the answeer is definitely silicon.