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Alenkinab [10]
3 years ago
6

A catalyst works by(1) increasing the potential energy of the reactants(2) increasing the energy released during a reaction(3) d

ecreasing the potential energy of the products(4) decreasing the activation energy required for a reaction

Chemistry
2 answers:
Ahat [919]3 years ago
8 0

Answer: Option (4) is the correct answer.

Explanation:

Activation energy is the minimum amount of energy required by reactant molecules to undergo a chemical reaction.

Whereas a catalyst is defined as the substance that helps in increasing the rate of reaction by decreasing the activation energy without itself getting consumed in the reaction.

When a catalyst decreases the activation energy then molecules with lesser energy become able to participate in the reaction and thus, products are obtained at a faster rate. Hence, a catalyst increases the rate of a reaction.

Thus, we can conclude that a catalyst works by decreasing the activation energy required for a reaction.

valentina_108 [34]3 years ago
7 0
The catalyst (4) decreases the activation energy required for a reaction, by holding reactants in place
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why do you think you can find silver and gold on their own in rocks but calcium and magnesium are combined with other elements t
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Explanation:

Silver and Gold belong to a special group of metals known as the native metals. They are found naturally on their own and not in combined form in rocks.

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A 20.0 g piece of a metal is heated and place into a calorimeter containing 250.0 g of water initially at 25.0 oC. The final tem
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4. When 1.00 L of 1.00 M Ba(NO3)2 solution at 25.0˚C is mixed with 1.00 L of 1.00 M Na2SO4 solution at 25.0˚C in a calorimeter,
myrzilka [38]

Answer:

The final temperature of the mixture is 28.11 °C

Explanation:

Step 1: Data given

Volume of 1.00 M Ba(NO3)2 = 1.00 L

Temperature = 25.0 °C

Volume of 1.00 M Na2SO4 = 1.00 L

enthalpy change is – 26 kJ per mol BaSO4

The specific heat of water is 4.18 J/g ·˚C

the density of water is 1.00 g/mL

Step 2: The balanced equation

Ba(NO3)2(aq) + Na2SO4(aq) → 2NaNO3(aq) + BaSO4(s)

Step 3: Calculate the total volume

Total volume = 1.00 L + 1.00 L = 2.00 L = 2000 mL

Step 4: Calculate mass

Mass = volume * density

Mass = 2000 mL * 1g/mL

Mass = 2000 grams

Step 5: Calculate moles BaSO4 formed

For 1 mol Ba(NO3)2 we need 1 mol Na2SO4 to produce 1 mol BaSO4

There is no limiting reactant, both Ba(NO3)2 and Na2SO4 will be completely be consumed (1 mol). We'll have 1.0 mol of BaSO4 produced.

Step 6: Calculate Q

Q = - ΔH

ΔH is negative so the reaction is exothermic, what means the temperature increases

Q is always positive, so Q = 26kJ = 26000 J

Step 6: Calculate the heat transfer

Q= m*c*ΔT

⇒with Q = the heat transfer = TO BE DETERMINED

⇒with m =the mass of the solution = 2000 grams

⇒with c= the specific heat of the solution = 4.18 J/g°C

⇒with ΔT = the change of temperature = T2 - T1 = T2 - 25.0

26000 = 2000 * 4.18 * (T2 - 25.0 °C)

3.11 = T2 - 25.0 °C

T2 = 25.0 + 3.11 °C

T2 = 28.11 °C

The final temperature of the mixture is 28.11 °C

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