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Alenkinab [10]
3 years ago
6

A catalyst works by(1) increasing the potential energy of the reactants(2) increasing the energy released during a reaction(3) d

ecreasing the potential energy of the products(4) decreasing the activation energy required for a reaction

Chemistry
2 answers:
Ahat [919]3 years ago
8 0

Answer: Option (4) is the correct answer.

Explanation:

Activation energy is the minimum amount of energy required by reactant molecules to undergo a chemical reaction.

Whereas a catalyst is defined as the substance that helps in increasing the rate of reaction by decreasing the activation energy without itself getting consumed in the reaction.

When a catalyst decreases the activation energy then molecules with lesser energy become able to participate in the reaction and thus, products are obtained at a faster rate. Hence, a catalyst increases the rate of a reaction.

Thus, we can conclude that a catalyst works by decreasing the activation energy required for a reaction.

valentina_108 [34]3 years ago
7 0
The catalyst (4) decreases the activation energy required for a reaction, by holding reactants in place
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How many liters of hydrogen gas will be produced at STP from the reaction of 7.179 x 1023 atoms of magnesium with 54.21 g of pho
wlad13 [49]
<h3>Answer:</h3>

18.58 liters of hydrogen gas

<h3>Explanation:</h3>

We are given;

  • The equation;

3Mg + 2H₃(PO₄) → Mg₃(PO₄)₂ + 3H₂

  • Atoms of Magnesium = 7.179 x 10^23 atoms
  • Mass of phosphoric acid as 54.21 g

We are required to determine the volume of hydrogen gas produced;

Step 1; moles of Magnesium

1 mole of an element contains 6.02 × 10^23 atoms

therefore;

Moles of Mg = (7.179 x 10^23 ) ÷ (6.02 × 10^23)

                   = 1.193 moles

Step 2: Moles of phosphoric acid

moles = Mass ÷ Molar mass

Molar mass of phosphoric acid = 97.994 g/mol

Therefore;

Moles of Phosphoric acid = 54.21 g ÷ 97.994 g/mol

                                           = 0.553 moles

Step 3: Determine the rate limiting reagent

From the mole ratio of Mg to Phosphoric acid (3 : 2);

1.193 moles of magnesium requires 0.795 moles of phosphoric acid while,

0.0553 moles of phosphoric acid requires 0.8295 moles of Mg

Therefore, phosphoric acid is the rate limiting reagent

step 4: Determine the moles of hydrogen produced

From the equation, w moles of phosphoric acid reacts to produce 3 moles of hydrogen;

Therefore; moles of Hydrogen = moles of phosphoric acid × 3/2

                                                   = 0.553 moles × 3/2

                                                   = 0.8295 moles

Step 5: Volume of hydrogen gas

1 mole of a gas occupies a volume of 22.4 liters at STP

Therefore;

Volume of Hydrogen = 0.8295 moles × 22.4 L/mol

                                  = 18.58 Liters

Therefore; 18.58 liters of hydrogen gas  will be produced

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3 years ago
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