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Vika [28.1K]
4 years ago
7

A force of 34.5 newtons is applied to an object at an angle of 45 º with the horizontal. What is the force acting on the object

in the horizontal direction?
Physics
1 answer:
ddd [48]4 years ago
6 0
The horizontal component of the force is 34.5 cos(45) = 24.4 newtons

The vertical component of the force is 34.5 sin(45) = 24.4 newtons
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An underwater diver sees the sun 57 ∘ above horizontal. how high is the sun above the horizon to a fisherman in a boat above the
nydimaria [60]

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Rearrange the Coulomb's Law formula to find distance(r)
lesantik [10]
<span>Coulomb's law describes the magnitude of the electrostatic force between two electric charges. The Coulomb's law formula is:
  <span>F = Ke * q1 * q2 / r2</span>

Where:
  q1: Charge of object 1
  q2: Charge of object 2
  r: Distance between the two objects
  F: Force between the two objects. A positive force implies a repulsive interaction, while a negative force implies an attractive interaction
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</span>
Coulomb's Law Examples:
What is the magnitude of the force between two protons which are 1.6E10-6 meters apart?

The charge of 1 proton is +1e (+1.602E-19 C).

F = 8.9875517873681764 * 109 * 1.602E-19 * 1.602E-19 / (1.6E-6 * 1.6 E-6) = 9 * 10-17 N


Source- http://www.endmemo.com/physics/coulomb.php




f = k (q^1)(q^2)/r^2

both sides by r^2 Multiply
fr^2/r^2 = kq^3/r^2

both sides by r^2 divide 
f = kq^3/r^2


Answer:
f = kq^3/r^2



Hope this helps!!!!


</span>
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Answer:

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