Answer and Solution:
As per the question:
The particle's displacement is given by the expression:
Now,
(a) The average velocity is given as the ratio of the displacement of the particle to the time interval:
Now, displacement in the interval:
i) [3,4]
At t = 3 s
At t = 4 s
ii) [3.5, 4]
At t = 3.5 s
At t = 4 s
iii) [4, 5]
At t = 4 s
At t = 5 s
iv) [4, 4.5]
At t = 4 s
At t = 4.5 s
(b) The instantaneous velocity at t = 4 s is given by:
At t = 4 s
Answer:
44.1 m
Explanation:
initial velocity of ball, u = 0
height of building, H = 106 m
g = 9.8 m/s^2
t = 3 second
Let the ball travels a distance of h in first 3 seconds.
Use second equation of motion
h = 0 + 0.5 x 9.8 x 3 x 3
h = 44.1 m
Thus, the distance traveled by the ball in first 3 seconds is 44.1 m.
Hmmm, id say cardio.. but i don't know forsure
Answer:
C. 5 miles/ minute north east
Explanation:
magnitude = 10 mi / 2 min = 5 mi/min
Velocity is a vector
A vector always has both a magnitude and direction
Explanation:
the answer to question one is complete the answer to question to is from negative to positive