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VladimirAG [237]
3 years ago
12

Carbon dioxide enters an adiabatic nozzle steadily at 1 MPa, 518 oC, and mass flow rate of 5,322 kg/h and exits the system at 96

kPa and 421 m/s. Considering the nozzle having an inlet area of 37 cm2, calculate the inlet velocity in m/s
Physics
1 answer:
Orlov [11]3 years ago
3 0

Answer:

The velocity at the nozzle at inlet V_{1} = 3584 \frac{m}{sec}

Explanation:

Pressure at inlet P_{1} = 1 × 10^{6} Pa

Temperature at inlet T_{1} = 518 ° c = 791 K

Mass flow rate = \frac{5322}{60} \frac{kg}{sec} = 88.7

Gas constant for carbon die oxide is R = 189 \frac{J}{kg k}

Mass flow rate inside the nozzle is given by the formula = \frac{P_{1} }{R T_{1} } × A_{1} × V_{1}

⇒ P_{1} = = 1 × 10^{6} Pa

⇒ RT_{1} = 791 × 189 = 149499 \frac{J}{kg}

⇒ A_{1} = 0.0037 m^{2}

Put all the above values in above formula we get,

⇒ 88.7 = \frac{10^{6} }{149499} × 0.0037 × V_{1}

⇒ V_{1} = 3584 \frac{m}{sec}

This is the velocity at the nozzle at inlet.

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A mover loads a 100 kg box into the back of a moving truck by
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Answer:

2.7

Explanation:

The following data were obtained from the question:

Mass (m) of box = 100 Kg

Length (L) of ramp = 4 m

Height (H) of ramp = 1.5 m

Mechanical advantage (MA) of ramp =?

Mechanical advantage of a ramp is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is given by:

Mechanical Advantage = Lenght / height

MA= L/H

With the above formula, we can obtain the mechanical advantage of the ramp as follow:

Length (L) of ramp = 4 m

Height (H) of ramp = 1.5 m

Mechanical advantage (MA) of ramp =?

MA = 4/1.5

MA = 2.7

Therefore, the mechanical advantage of the ramp is 2.7

3 0
2 years ago
Question 1 of 10
ivanzaharov [21]
The answer would be 46.482 because you multiply 18.3 by 2.54 because for every inch you get 2.54 centimeters
6 0
1 year ago
Read 2 more answers
Is the relationship between velocity and centripetal force a direct, linear or nonlinear square relationship?
Svet_ta [14]

Answer:

non linear square relationship

Explanation:

formula for centripetal force is given as

a = mv^2/r

here a ic centripetal acceleration , m is mass of body moving in circle of radius r and v is velocity of body . If m ,and r are constant we have

a = constant × v^2

a α v^2

hence non linear square relationship

5 0
3 years ago
A seagull flies at a velocity of 9.00 m/s straight into the wind. (a) if it takes the bird 20.0 min to travel 6.00 km relative t
enot [183]

Here we will the speed of seagull which is v = 9 m/s

this is the speed of seagull when there is no effect of wind on it

now in part a)

if effect of wind is in opposite direction then it travels 6 km in 20 min

so the average speed is given by the ratio of total distance and total time

v_{avg} = \frac{6000}{20*60}

v_{avg} = 5m/s

now since effect of wind is in opposite direction then we can say

V_{net} = v_{bird} - v_{wind}

5 = 9 - v_{wind}

v_{wind}= 4 m/s

Part b)

now if bird travels in the same direction of wind then we will have

v_{net}= v_{bird} + v_{wind}

v_{net} = 9 + 4 = 13 m/s

now we can find the time to go back

time = \frac{distance}{speed}

time = \frac{6000}{13}

time = 7.7 minutes

Part c)

Total time of round trip when wind is present

T = t_1 + t_2

T = 20 + 7.7 = 27.7 min

now when there is no wind total time is given by

T = \frac{6000}{9} + \frac{6000}{9}

T = 22.22 min

So due to wind time will be more

4 0
3 years ago
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