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VladimirAG [237]
3 years ago
12

Carbon dioxide enters an adiabatic nozzle steadily at 1 MPa, 518 oC, and mass flow rate of 5,322 kg/h and exits the system at 96

kPa and 421 m/s. Considering the nozzle having an inlet area of 37 cm2, calculate the inlet velocity in m/s
Physics
1 answer:
Orlov [11]3 years ago
3 0

Answer:

The velocity at the nozzle at inlet V_{1} = 3584 \frac{m}{sec}

Explanation:

Pressure at inlet P_{1} = 1 × 10^{6} Pa

Temperature at inlet T_{1} = 518 ° c = 791 K

Mass flow rate = \frac{5322}{60} \frac{kg}{sec} = 88.7

Gas constant for carbon die oxide is R = 189 \frac{J}{kg k}

Mass flow rate inside the nozzle is given by the formula = \frac{P_{1} }{R T_{1} } × A_{1} × V_{1}

⇒ P_{1} = = 1 × 10^{6} Pa

⇒ RT_{1} = 791 × 189 = 149499 \frac{J}{kg}

⇒ A_{1} = 0.0037 m^{2}

Put all the above values in above formula we get,

⇒ 88.7 = \frac{10^{6} }{149499} × 0.0037 × V_{1}

⇒ V_{1} = 3584 \frac{m}{sec}

This is the velocity at the nozzle at inlet.

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for an ideal monoatomic gas, the internal energy U os due to the kinetic energy and U=3/2RT per mole.show that cv=3/2R per mole
sladkih [1.3K]

Answer:

i. Cv =3R/2

ii. Cp = 5R/2

Explanation:

i. Cv = Molar heat capacity at constant volume

Since the internal energy of the ideal monoatomic gas is U = 3/2RT and Cv = dU/dT

Differentiating U with respect to T, we have

= d(3/2RT)/dT

= 3R/2

ii. Cp - Molar heat capacity at constant pressure

Cp = Cv + R

substituting Cv into the equation, we have

Cp = 3R/2 + R

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3 years ago
If an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 millimeters in front o
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The correct answer is letter A. 6 millimeters. <span>If an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 millimeters in front of the lens, the height of the image is 6 millimeters.
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7 0
3 years ago
Un alambre de teléfono de 120m de largo y de 2.2mm de diámetro se estira debido a una fuerza de 380 N cual es el esfuerzo longit
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Respuesta: verifique amablemente la explicación

Explicación:

Dado lo siguiente:

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Diámetro (d) = 2,2 mm (2,2 / 1000) = 2,2 * 10 ^ -3 m

Fuerza (F) = 380 N

Esfuerzo longitudinal = Fuerza / Área

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Estrés = Fuerza / Área

Estrés = 380 / 0.00000380132

Esfuerzo longitudinal = 99952128.12 = 9.9952128 * 10^7 Nm^-2

Deformación longitudinal: extensión / longitud

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Longitud = 120 m

Deformación longitudinal = 0,1 m / 120 m

Deformación longitudinal = 0.0008333 = 8.33 × 10 ^ -4

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