Answer:
b) C = 0.50 J/(g°C)
Explanation:
∴ Q = 50 J
∴ m = 10.0 g
∴ ΔT = 35 - 25 = 10 °C
specific heat (C) :
⇒ C = Q / mΔT
⇒ C = 50 J / (10.0 g)(10 °C)
⇒ C = 0.50 J/(g°C)
Answer: 7.07 grams
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of 
require 1 mole of 
Thus 0.052 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 1 mole of give = 1 mole of 
Thus 0.052 moles of give = of
Mass of 
Thus 7.07 g of will be produced from the given masses of both reactants.
N= m/v n=0.077/.200 = 0.385
Answer:
Mark me brainlist I will then answer in comment
Answer:
<h2>10 g</h2>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volume
From the question we have
mass = 2 × 5
We have the final answer as
<h3>10 g</h3>
Hope this helps you
